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Chromium is a transition metal, and oxygen has an oxidation number of -2. Use this information to match each compound to its chemical formula.

Chromium(I) oxide: [tex]Cr_2O[/tex] [tex]\(\square\)[/tex]
Chromium(II) oxide: [tex]CrO[/tex] [tex]\(\square\)[/tex]
Chromium(IV) oxide: [tex]CrO_2[/tex] [tex]\(\square\)[/tex]
Chromium(VI) oxide: [tex]CrO_3[/tex] [tex]\(\square\)[/tex]

Sagot :

GinnyAnsweridn
Certainly! Let's match each compound of Chromium with its correct chemical formula:

1. Chromium(I) oxide: Chromium in the +1 oxidation state.
- To neutralize the charges, we need two chromium ions (+1 each) to balance one oxygen ion (-2).
- Chemical formula: Cr₂O

2. Chromium(II) oxide: Chromium in the +2 oxidation state.
- To neutralize the charges, we need one chromium ion (+2) to balance one oxygen ion (-2).
- Chemical formula: CrO

3. Chromium(IV) oxide: Chromium in the +4 oxidation state.
- To neutralize the charges, we need one chromium ion (+4) to balance two oxygen ions (-2 each).
- Chemical formula: CrO₂

4. Chromium(VI) oxide: Chromium in the +6 oxidation state.
- To neutralize the charges, we need one chromium ion (+6) to balance three oxygen ions (-2 each).
- Chemical formula: CrO₃

So, the correct matches are:
- Chromium(I) oxide ⟶ Cr₂O
- Chromium(II) oxide ⟶ CrO
- Chromium(IV) oxide ⟶ CrO₂
- Chromium(VI) oxide ⟶ CrO₃
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