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There are 6 adult chaperones, 21 female students, and 23 male students on a bus for a field trip.

What is the probability that a randomly chosen person on the bus is an adult chaperone or a male student?

A. [tex]\frac{1}{2}[/tex]
B. [tex]\frac{1}{29}[/tex]
C. [tex]\frac{2}{3}[/tex]
D. [tex]\frac{29}{50}[/tex]

Sagot :

GinnyAnsweridn
Certainly! Let's solve this problem step-by-step.

1. Determine the total number of people on the bus:

- Number of adult chaperones: 6
- Number of female students: 21
- Number of male students: 23

Total number of people on the bus = 6 (chaperones) + 21 (female students) + 23 (male students)

[tex]\[ \text{Total people on the bus} = 6 + 21 + 23 = 50 \][/tex]

2. Determine the number of favorable outcomes:

We need to find the number of people who are either adult chaperones or male students.

- Number of adult chaperones: 6
- Number of male students: 23

The number of people who fall into either category = 6 (chaperones) + 23 (male students)

[tex]\[ \text{Favorable outcomes} = 6 + 23 = 29 \][/tex]

3. Calculate the probability that a randomly chosen person is an adult chaperone or a male student:

The probability of an event is given by the number of favorable outcomes divided by the total number of possible outcomes.

[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of people}} \][/tex]

Substituting the numbers we found:

[tex]\[ \text{Probability} = \frac{29}{50} \][/tex]

So, the probability that a randomly chosen person on the bus is an adult chaperone or a male student is [tex]\(\frac{29}{50}\)[/tex].

Thus, the correct answer is [tex]\( \boxed{ \frac{29}{50} } \)[/tex].
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