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Sagot :
To determine the volume of a large emerald given its mass and density, we need to use the formula for volume based on mass and density:
[tex]\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \][/tex]
Given data:
- Mass of the emerald [tex]\( = 982.7 \)[/tex] grams
- Density of the emerald [tex]\( = 276 \frac{\text{grams}}{\text{cm}^3} \)[/tex]
Substitute the given values into the formula:
[tex]\[ \text{Volume} = \frac{982.7}{276} \][/tex]
Perform the division:
[tex]\[ \frac{982.7}{276} \approx 3.5605072463768117 \][/tex]
We need to round the volume to the nearest hundredth:
[tex]\[ \text{Volume} \approx 3.56 \][/tex]
Thus, the volume of the emerald is:
[tex]\[ 3.56 \ \text{cm}^3 \][/tex]
Answer for Blank 1: 3.56
[tex]\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \][/tex]
Given data:
- Mass of the emerald [tex]\( = 982.7 \)[/tex] grams
- Density of the emerald [tex]\( = 276 \frac{\text{grams}}{\text{cm}^3} \)[/tex]
Substitute the given values into the formula:
[tex]\[ \text{Volume} = \frac{982.7}{276} \][/tex]
Perform the division:
[tex]\[ \frac{982.7}{276} \approx 3.5605072463768117 \][/tex]
We need to round the volume to the nearest hundredth:
[tex]\[ \text{Volume} \approx 3.56 \][/tex]
Thus, the volume of the emerald is:
[tex]\[ 3.56 \ \text{cm}^3 \][/tex]
Answer for Blank 1: 3.56
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