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Q#6: Multiply these expressions using the FOIL method.

a) [tex]\((x+5)\)[/tex] and [tex]\((x+3)\)[/tex]

b) [tex]\((x+5)\)[/tex] and [tex]\((x-5)\)[/tex]

c) [tex]\((2x-9)\)[/tex] and [tex]\((4x-7)\)[/tex]

d) [tex]\((x-5)\)[/tex] and [tex]\((x-3)\)[/tex]

e) [tex]\((7x-5)\)[/tex] and [tex]\((4x+3)\)[/tex]

Sagot :

GinnyAnsweridn
Alright, let's solve each part of this question using the FOIL method. FOIL stands for First, Outer, Inner, Last, and it is a method used to multiply two binomials.

### a) [tex]\((x + 5)\)[/tex] and [tex]\((x + 3)\)[/tex]
Applying the FOIL method:
- First: [tex]\(x \cdot x = x^2\)[/tex]
- Outer: [tex]\(x \cdot 3 = 3x\)[/tex]
- Inner: [tex]\(5 \cdot x = 5x\)[/tex]
- Last: [tex]\(5 \cdot 3 = 15\)[/tex]

Combine all these terms:
[tex]\[ x^2 + 3x + 5x + 15 = x^2 + 8x + 15 \][/tex]

Result: [tex]\( x^2 + 8x + 15 \)[/tex]

### b) [tex]\((x + 5)\)[/tex] and [tex]\((x - 5)\)[/tex]
Applying the FOIL method:
- First: [tex]\(x \cdot x = x^2\)[/tex]
- Outer: [tex]\(x \cdot (-5) = -5x\)[/tex]
- Inner: [tex]\(5 \cdot x = 5x\)[/tex]
- Last: [tex]\(5 \cdot (-5) = -25\)[/tex]

Combine all these terms:
[tex]\[ x^2 - 5x + 5x - 25 = x^2 - 25 \][/tex]

Result: [tex]\( x^2 - 25 \)[/tex]

### c) [tex]\((2x - 9)\)[/tex] and [tex]\((4x - 7)\)[/tex]
Applying the FOIL method:
- First: [tex]\(2x \cdot 4x = 8x^2\)[/tex]
- Outer: [tex]\(2x \cdot (-7) = -14x\)[/tex]
- Inner: [tex]\(-9 \cdot 4x = -36x\)[/tex]
- Last: [tex]\(-9 \cdot (-7) = 63\)[/tex]

Combine all these terms:
[tex]\[ 8x^2 - 14x - 36x + 63 = 8x^2 - 50x + 63 \][/tex]

Result: [tex]\( 8x^2 - 50x + 63 \)[/tex]

### d) [tex]\((x - 5)\)[/tex] and [tex]\((x - 3)\)[/tex]
Applying the FOIL method:
- First: [tex]\(x \cdot x = x^2\)[/tex]
- Outer: [tex]\(x \cdot (-3) = -3x\)[/tex]
- Inner: [tex]\(-5 \cdot x = -5x\)[/tex]
- Last: [tex]\(-5 \cdot (-3) = 15\)[/tex]

Combine all these terms:
[tex]\[ x^2 - 3x - 5x + 15 = x^2 - 8x + 15 \][/tex]

Result: [tex]\( x^2 - 8x + 15 \)[/tex]

### e) [tex]\((7x - 5)\)[/tex] and [tex]\((4x + 3)\)[/tex]
Applying the FOIL method:
- First: [tex]\(7x \cdot 4x = 28x^2\)[/tex]
- Outer: [tex]\(7x \cdot 3 = 21x\)[/tex]
- Inner: [tex]\(-5 \cdot 4x = -20x\)[/tex]
- Last: [tex]\(-5 \cdot 3 = -15\)[/tex]

Combine all these terms:
[tex]\[ 28x^2 + 21x - 20x - 15 = 28x^2 + x - 15 \][/tex]

Result: [tex]\( 28x^2 + x - 15 \)[/tex]

So the final results for the given multiplications are:

a) [tex]\( x^2 + 8x + 15 \)[/tex]

b) [tex]\( x^2 - 25 \)[/tex]

c) [tex]\( 8x^2 - 50x + 63 \)[/tex]

d) [tex]\( x^2 - 8x + 15 \)[/tex]

e) [tex]\( 28x^2 + x - 15 \)[/tex]
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