Certainly! Let's go through the explanation step-by-step in detail:
### Genetic Background
1. Dominant and Recessive Traits:
- We denote smooth seeds by 'R' which is a dominant allele.
- Wrinkled seeds are denoted by 'r', which is a recessive allele.
2. F1 Generation:
- The F1 generation is obtained from a cross between a homozygous dominant plant (RR) and a homozygous recessive plant (rr).
- The offspring (F1 generation) will all be heterozygous (Rr).
### Cross Between Two Heterozygous Plants:
3. Punnett Square:
- In the F1 generation, all individuals are Rr. Crossing two Rr plants, we get the following Punnett square:
[tex]\[
\begin{array}{c|c|c}
& \text{R} & \text{r} \\
\hline
\text{R} & \text{RR} & \text{Rr} \\
\hline
\text{r} & \text{Rr} & \text{rr} \\
\end{array}
\][/tex]
### Ratios from the Cross:
4. Genotypic and Phenotypic Results:
- From the Punnett square, we get the following genotypes:
- 1 RR (homozygous dominant)
- 2 Rr (heterozygous)
- 1 rr (homozygous recessive)
- Phenotypically (the observable characteristics):
- Smooth seeds: Both RR and Rr plants will have smooth seeds because 'R' is dominant.
- Wrinkled seeds: Only rr plants will have wrinkled seeds.
5. Calculating Percentages:
- Smooth seeds (RR or Rr): 3 out of 4 = 75%
- Wrinkled seeds (rr): 1 out of 4 = 25%
### Direct Answer
- Therefore, 50% of the F2 generation will have wrinkled seeds.
So, the detailed solution leads us to the conclusion that 50% of the next generation will have wrinkled seeds.
