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Sagot :
To solve this problem, let's follow the steps to use the first equation to substitute for [tex]\( y \)[/tex] in the second equation and then combine like terms.
Given equations:
[tex]\[ \begin{array}{l} y = 2x \\ 2x + 3y = 16 \end{array} \][/tex]
1. Substitute [tex]\( y = 2x \)[/tex] from the first equation into the second equation:
[tex]\[ 2x + 3(2x) = 16 \][/tex]
2. Simplify by distributing the [tex]\( 3 \)[/tex] through the [tex]\( 2x \)[/tex] inside the parentheses:
[tex]\[ 2x + 6x = 16 \][/tex]
3. Combine like terms (both [tex]\( 2x \)[/tex] and [tex]\( 6x \)[/tex] are terms involving [tex]\( x \)[/tex]):
[tex]\[ 8x = 16 \][/tex]
Therefore, the correct result after substituting for [tex]\( y \)[/tex] and combining like terms is:
[tex]\[ \boxed{8x = 16} \][/tex]
The correct answer is:
A. [tex]\( 8x = 16 \)[/tex]
Given equations:
[tex]\[ \begin{array}{l} y = 2x \\ 2x + 3y = 16 \end{array} \][/tex]
1. Substitute [tex]\( y = 2x \)[/tex] from the first equation into the second equation:
[tex]\[ 2x + 3(2x) = 16 \][/tex]
2. Simplify by distributing the [tex]\( 3 \)[/tex] through the [tex]\( 2x \)[/tex] inside the parentheses:
[tex]\[ 2x + 6x = 16 \][/tex]
3. Combine like terms (both [tex]\( 2x \)[/tex] and [tex]\( 6x \)[/tex] are terms involving [tex]\( x \)[/tex]):
[tex]\[ 8x = 16 \][/tex]
Therefore, the correct result after substituting for [tex]\( y \)[/tex] and combining like terms is:
[tex]\[ \boxed{8x = 16} \][/tex]
The correct answer is:
A. [tex]\( 8x = 16 \)[/tex]
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