To determine the concentration of ethyl alcohol in the solution when 10 mL of ethyl alcohol is mixed with 90 mL of water, follow these steps:
1. Calculate the total volume of the solution:
- You have 10 mL of ethyl alcohol.
- You have 90 mL of water.
- Therefore, the total volume of the solution is:
[tex]\[
\text{Total volume} = \text{Volume of ethyl alcohol} + \text{Volume of water}
\][/tex]
Substituting the given values:
[tex]\[
\text{Total volume} = 10 \, \text{mL} + 90 \, \text{mL} = 100 \, \text{mL}
\][/tex]
2. Calculate the concentration of ethyl alcohol in the solution:
- The concentration in percentage is given by the formula:
[tex]\[
\text{Concentration} = \left( \frac{\text{Volume of ethyl alcohol}}{\text{Total volume of the solution}} \right) \times 100
\][/tex]
Substituting the values we have:
[tex]\[
\text{Concentration} = \left( \frac{10 \, \text{mL}}{100 \, \text{mL}} \right) \times 100 = 10\%
\][/tex]
So, the concentration of ethyl alcohol in the solution is 10%. Therefore, when 10 mL of ethyl alcohol is mixed with 90 mL of water, the total volume of the solution is 100 mL, and the concentration of ethyl alcohol in the solution is 10%.
