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What is the constant of variation, [tex]$k$[/tex], of the direct variation, [tex]$y = kx$[/tex], through [tex][tex]$(-3, 2)$[/tex][/tex]?

A. [tex]$k = \frac{3}{2}$[/tex]

B. [tex]$k = \frac{2}{3}$[/tex]

C. [tex][tex]$k = \frac{2}{3}$[/tex][/tex]

D. [tex]$k = \frac{3}{2}$[/tex]


Sagot :

To determine the constant of variation, [tex]\( k \)[/tex], for the direct variation equation [tex]\( y = kx \)[/tex] through the point [tex]\((-3, 2)\)[/tex], we can follow these steps:

1. Identify the given point:
- We are given the coordinates [tex]\((x, y) = (-3, 2)\)[/tex].

2. Write the direct variation equation:
- The equation for direct variation is [tex]\( y = kx \)[/tex].

3. Substitute the given point into the equation:
- Substitute [tex]\( x = -3 \)[/tex] and [tex]\( y = 2 \)[/tex] into the equation [tex]\( y = kx \)[/tex]:
[tex]\[ 2 = k(-3) \][/tex]

4. Solve for [tex]\( k \)[/tex]:
- Isolate [tex]\( k \)[/tex] by dividing both sides of the equation by [tex]\(-3\)[/tex]:
[tex]\[ k = \frac{2}{-3} \][/tex]

5. Simplify the expression:
- [tex]\(\frac{2}{-3}\)[/tex] simplifies to [tex]\(-\frac{2}{3}\)[/tex].

Therefore, the constant of variation, [tex]\( k \)[/tex], is [tex]\(-\frac{2}{3}\)[/tex]. The correct answer is not listed among the choices given as they seem to have positive constants, but based on the steps we have followed, the actual constant is [tex]\(-\frac{2}{3}\)[/tex].