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Solve the inequality.

[tex]\[ \left|18 + \frac{x}{2}\right| \geq 10 \][/tex]

[tex]\[ x \leq \ ? \text{ or } x \geq \ ? \][/tex]


Sagot :

Sure, let's solve the inequality step-by-step:

Given inequality:
[tex]\[ \left|18 + \frac{x}{2} \right| \geq 10 \][/tex]

To solve this absolute value inequality, we'll break it into two separate inequalities based on the definition of absolute value [tex]\( |A| \geq B \)[/tex] which translates to [tex]\( A \geq B \)[/tex] or [tex]\( A \leq -B \)[/tex].

#### Step 1: Split the inequality into two cases

1. Case 1:
[tex]\[ 18 + \frac{x}{2} \geq 10 \][/tex]

2. Case 2:
[tex]\[ 18 + \frac{x}{2} \leq -10 \][/tex]

#### Step 2: Solve each case individually

Case 1:
[tex]\[ 18 + \frac{x}{2} \geq 10 \][/tex]

Subtract 18 from both sides:
[tex]\[ \frac{x}{2} \geq 10 - 18 \][/tex]

[tex]\[ \frac{x}{2} \geq -8 \][/tex]

Multiply both sides by 2:
[tex]\[ x \geq -16 \][/tex]

Case 2:
[tex]\[ 18 + \frac{x}{2} \leq -10 \][/tex]

Subtract 18 from both sides:
[tex]\[ \frac{x}{2} \leq -10 - 18 \][/tex]

[tex]\[ \frac{x}{2} \leq -28 \][/tex]

Multiply both sides by 2:
[tex]\[ x \leq -56 \][/tex]

#### Step 3: Combine the solutions

The solutions from both cases are:
[tex]\[ x \leq -56 \quad \text{or} \quad x \geq -16 \][/tex]

So, the final solution to the inequality [tex]\(\left|18 + \frac{x}{2}\right| \geq 10\)[/tex] is:
[tex]\[ x \leq -56 \quad \text{or} \quad x \geq -16 \][/tex]

We can write this in interval notation as:
[tex]\[ (-\infty, -56] \cup [-16, \infty) \][/tex]

Thus, the answer is:
[tex]\[ x \leq -56 \quad \text{or} \quad x \geq -16. \][/tex]
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