Join the growing community of curious minds on IDNLearn.com and get the answers you need. Explore a wide array of topics and find reliable answers from our experienced community members.

What is the specific heat capacity of a 14.407 g metal that absorbs 218.17 J of heat if it undergoes a 37.9°C temperature change?

Sagot :

To find the specific heat capacity of the metal, we can use the formula for specific heat capacity ([tex]\(c\)[/tex]):

[tex]\[ c = \frac{Q}{m \Delta T} \][/tex]

where:
- [tex]\( Q \)[/tex] is the amount of heat absorbed (in Joules, [tex]\(J\)[/tex]),
- [tex]\( m \)[/tex] is the mass of the metal (in grams, [tex]\(g\)[/tex]),
- [tex]\(\Delta T\)[/tex] is the temperature change (in degrees Celsius, [tex]\(°C\)[/tex]).

Given the values:
- [tex]\( Q = 218.17 \, J \)[/tex]
- [tex]\( m = 14.407 \, g \)[/tex]
- [tex]\(\Delta T = 37.9 \, °C\)[/tex]

we can substitute these values into the formula to find [tex]\( c \)[/tex]:

[tex]\[ c = \frac{218.17 \, J}{14.407 \, g \times 37.9 \, °C} \][/tex]

First, we carry out the multiplication in the denominator:

[tex]\[ 14.407 \, g \times 37.9 \, °C = 546.0453 \, g \cdot °C \][/tex]

Now, we divide the numerator by this product:

[tex]\[ c = \frac{218.17 \, J}{546.0453 \, g \cdot °C} \][/tex]

[tex]\[ c \approx 0.39956024015736996 \, \frac{J}{g \cdot °C} \][/tex]

Therefore, the specific heat capacity of the metal is approximately [tex]\(0.400 \, \frac{J}{g \cdot °C}\)[/tex] (rounded to three decimal places).
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.