Experience the power of community-driven knowledge on IDNLearn.com. Join our community to receive prompt and reliable responses to your questions from knowledgeable professionals.
Sagot :
Certainly! Let's go through the step-by-step solution to determine the volume inside the event horizon of a black hole with a given mass [tex]\( M \)[/tex].
### Step 1: Understand the Inputs and Constants
1. Gravitational Constant ([tex]\( G \)[/tex]): [tex]\( G = 6.67430 \times 10^{-11} \, \text{m}^3 \text{kg}^{-1} \text{s}^{-2} \)[/tex]
2. Speed of Light ([tex]\( c \)[/tex]): [tex]\( c = 299792458 \, \text{m/s} \)[/tex]
3. Mass of the Sun ([tex]\( M_{\odot} \)[/tex]): [tex]\( M_{\odot} = 1.989 \times 10^{30} \, \text{kg} \)[/tex]
4. Mass of the Black Hole ([tex]\( M \)[/tex]): Let's assume it is 10 times the mass of the Sun. Therefore, [tex]\( M = 10 \, M_{\odot} = 10 \times 1.989 \times 10^{30} \, \text{kg} = 1.989 \times 10^{31} \, \text{kg} \)[/tex].
### Step 2: Calculate the Schwarzschild Radius
The Schwarzschild radius [tex]\( R_s \)[/tex] is given by the formula:
[tex]\[ R_s = \frac{2 G M}{c^2} \][/tex]
Plug in the known values:
[tex]\[ R_s = \frac{2 \times 6.67430 \times 10^{-11} \times 1.989 \times 10^{31}}{(299792458)^2} \][/tex]
After performing the calculation:
[tex]\[ R_s = 29541.27 \, \text{meters} \][/tex]
### Step 3: Calculate the Volume Inside the Event Horizon
The volume [tex]\( V \)[/tex] inside the event horizon is given by the formula for the volume of a sphere:
[tex]\[ V = \frac{4}{3} \pi R_s^3 \][/tex]
Plug in the Schwarzschild radius:
[tex]\[ V = \frac{4}{3} \pi (29541.27)^3 \][/tex]
### Step 4: Perform the Final Calculation
[tex]\[ V = \frac{4}{3} \pi (29541.27)^3 \][/tex]
After performing the calculation:
[tex]\[ V = 1.07988 \times 10^{14} \, \text{m}^3 \][/tex]
### Summary of the Solution
- Gravitational Constant (G): [tex]\(6.67430 \times 10^{-11} \, \text{m}^3 \text{kg}^{-1} \text{s}^{-2} \)[/tex]
- Speed of Light (c): [tex]\(299792458 \, \text{m/s} \)[/tex]
- Mass of the Sun ([tex]\( M_{\odot} \)[/tex]): [tex]\(1.989 \times 10^{30} \, \text{kg} \)[/tex]
- Mass of the Black Hole (M): [tex]\(1.989 \times 10^{31} \, \text{kg} \)[/tex]
- Schwarzschild Radius ([tex]\( R_s \)[/tex]): [tex]\(29541.27 \, \text{m} \)[/tex]
- Volume inside the Event Horizon: [tex]\(1.07988 \times 10^{14} \, \text{m}^3 \)[/tex]
This comprehensive calculation determines the volume inside the event horizon of a black hole with a mass 10 times that of the Sun.
### Step 1: Understand the Inputs and Constants
1. Gravitational Constant ([tex]\( G \)[/tex]): [tex]\( G = 6.67430 \times 10^{-11} \, \text{m}^3 \text{kg}^{-1} \text{s}^{-2} \)[/tex]
2. Speed of Light ([tex]\( c \)[/tex]): [tex]\( c = 299792458 \, \text{m/s} \)[/tex]
3. Mass of the Sun ([tex]\( M_{\odot} \)[/tex]): [tex]\( M_{\odot} = 1.989 \times 10^{30} \, \text{kg} \)[/tex]
4. Mass of the Black Hole ([tex]\( M \)[/tex]): Let's assume it is 10 times the mass of the Sun. Therefore, [tex]\( M = 10 \, M_{\odot} = 10 \times 1.989 \times 10^{30} \, \text{kg} = 1.989 \times 10^{31} \, \text{kg} \)[/tex].
### Step 2: Calculate the Schwarzschild Radius
The Schwarzschild radius [tex]\( R_s \)[/tex] is given by the formula:
[tex]\[ R_s = \frac{2 G M}{c^2} \][/tex]
Plug in the known values:
[tex]\[ R_s = \frac{2 \times 6.67430 \times 10^{-11} \times 1.989 \times 10^{31}}{(299792458)^2} \][/tex]
After performing the calculation:
[tex]\[ R_s = 29541.27 \, \text{meters} \][/tex]
### Step 3: Calculate the Volume Inside the Event Horizon
The volume [tex]\( V \)[/tex] inside the event horizon is given by the formula for the volume of a sphere:
[tex]\[ V = \frac{4}{3} \pi R_s^3 \][/tex]
Plug in the Schwarzschild radius:
[tex]\[ V = \frac{4}{3} \pi (29541.27)^3 \][/tex]
### Step 4: Perform the Final Calculation
[tex]\[ V = \frac{4}{3} \pi (29541.27)^3 \][/tex]
After performing the calculation:
[tex]\[ V = 1.07988 \times 10^{14} \, \text{m}^3 \][/tex]
### Summary of the Solution
- Gravitational Constant (G): [tex]\(6.67430 \times 10^{-11} \, \text{m}^3 \text{kg}^{-1} \text{s}^{-2} \)[/tex]
- Speed of Light (c): [tex]\(299792458 \, \text{m/s} \)[/tex]
- Mass of the Sun ([tex]\( M_{\odot} \)[/tex]): [tex]\(1.989 \times 10^{30} \, \text{kg} \)[/tex]
- Mass of the Black Hole (M): [tex]\(1.989 \times 10^{31} \, \text{kg} \)[/tex]
- Schwarzschild Radius ([tex]\( R_s \)[/tex]): [tex]\(29541.27 \, \text{m} \)[/tex]
- Volume inside the Event Horizon: [tex]\(1.07988 \times 10^{14} \, \text{m}^3 \)[/tex]
This comprehensive calculation determines the volume inside the event horizon of a black hole with a mass 10 times that of the Sun.
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.