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Answer:
8.46 years
Step-by-step explanation:
You want to know how long it takes for an investment of $3000 earning 3.4% interest compounded continuously to have a value of $4000.
The value of the investment P earning rate r for t years is ...
[tex]A=Pe^{rt}[/tex]
Solving for t, we find ...
[tex]\dfrac{A}{P}=e^{rt}\\\\t=\dfrac{\ln(\dfrac{A}{P})}{r}=\dfrac{\ln(\dfrac{4000}{3000})}{0.034}\approx8.46[/tex]
It will take about 8.46 years for the investment to be worth $4000.