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Sagot :
To calculate the pH of a solution given the concentration of hydrogen ions [tex]\(\left[ H^{+} \right]\)[/tex], we use the formula:
[tex]\[ \text{pH} = -\log \left[ H^{+} \right] \][/tex]
In this case, we are given that the concentration of hydrogen ions [tex]\(\left[ H^{+} \right]\)[/tex] is 0.01 M.
Step-by-step, the solution is as follows:
1. The given concentration of [tex]\( \left[ H^{+} \right] \)[/tex] is 0.01 M.
2. We need to find the logarithm (base 10) of this concentration.
3. Substitute the concentration value into the formula:
[tex]\[ \text{pH} = -\log \left( 0.01 \right) \][/tex]
4. The logarithm of 0.01 (which is [tex]\( 10^{-2} \)[/tex]) is -2:
[tex]\[ \log \left( 0.01 \right) = \log \left( 10^{-2} \right) = -2 \][/tex]
5. Applying the negative sign to the logarithm:
[tex]\[ \text{pH} = -(-2) \][/tex]
6. Therefore, the pH is:
[tex]\[ \text{pH} = 2 \][/tex]
So, the correct answer is:
[tex]\[ \boxed{2} \][/tex]
[tex]\[ \text{pH} = -\log \left[ H^{+} \right] \][/tex]
In this case, we are given that the concentration of hydrogen ions [tex]\(\left[ H^{+} \right]\)[/tex] is 0.01 M.
Step-by-step, the solution is as follows:
1. The given concentration of [tex]\( \left[ H^{+} \right] \)[/tex] is 0.01 M.
2. We need to find the logarithm (base 10) of this concentration.
3. Substitute the concentration value into the formula:
[tex]\[ \text{pH} = -\log \left( 0.01 \right) \][/tex]
4. The logarithm of 0.01 (which is [tex]\( 10^{-2} \)[/tex]) is -2:
[tex]\[ \log \left( 0.01 \right) = \log \left( 10^{-2} \right) = -2 \][/tex]
5. Applying the negative sign to the logarithm:
[tex]\[ \text{pH} = -(-2) \][/tex]
6. Therefore, the pH is:
[tex]\[ \text{pH} = 2 \][/tex]
So, the correct answer is:
[tex]\[ \boxed{2} \][/tex]
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