Get the most out of your questions with IDNLearn.com's extensive resources. Get timely and accurate answers to your questions from our dedicated community of experts who are here to help you.
Sagot :
To find the distance between the two points [tex]\( P = (3, 1) \)[/tex] and [tex]\( Q = (-3, -7) \)[/tex], we use the distance formula. The distance formula between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] in a coordinate plane is given by:
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Here, the coordinates are:
- [tex]\( P = (3, 1) \)[/tex] which gives [tex]\( x_1 = 3 \)[/tex] and [tex]\( y_1 = 1 \)[/tex].
- [tex]\( Q = (-3, -7) \)[/tex] which gives [tex]\( x_2 = -3 \)[/tex] and [tex]\( y_2 = -7 \)[/tex].
Substituting these values into the distance formula, we have:
[tex]\[ d = \sqrt{((-3) - 3)^2 + ((-7) - 1)^2} \][/tex]
Let's simplify the expression inside the square root step by step:
1. Calculate the difference in the x-coordinates:
[tex]\[ x_2 - x_1 = -3 - 3 = -6 \][/tex]
2. Calculate the difference in the y-coordinates:
[tex]\[ y_2 - y_1 = -7 - 1 = -8 \][/tex]
3. Square each of these differences:
[tex]\[ (-6)^2 = 36 \][/tex]
[tex]\[ (-8)^2 = 64 \][/tex]
4. Add the squares of the differences:
[tex]\[ 36 + 64 = 100 \][/tex]
5. Finally, take the square root of the sum:
[tex]\[ \sqrt{100} = 10 \][/tex]
Therefore, the distance [tex]\( PQ \)[/tex] is [tex]\( 10.0 \)[/tex].
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Here, the coordinates are:
- [tex]\( P = (3, 1) \)[/tex] which gives [tex]\( x_1 = 3 \)[/tex] and [tex]\( y_1 = 1 \)[/tex].
- [tex]\( Q = (-3, -7) \)[/tex] which gives [tex]\( x_2 = -3 \)[/tex] and [tex]\( y_2 = -7 \)[/tex].
Substituting these values into the distance formula, we have:
[tex]\[ d = \sqrt{((-3) - 3)^2 + ((-7) - 1)^2} \][/tex]
Let's simplify the expression inside the square root step by step:
1. Calculate the difference in the x-coordinates:
[tex]\[ x_2 - x_1 = -3 - 3 = -6 \][/tex]
2. Calculate the difference in the y-coordinates:
[tex]\[ y_2 - y_1 = -7 - 1 = -8 \][/tex]
3. Square each of these differences:
[tex]\[ (-6)^2 = 36 \][/tex]
[tex]\[ (-8)^2 = 64 \][/tex]
4. Add the squares of the differences:
[tex]\[ 36 + 64 = 100 \][/tex]
5. Finally, take the square root of the sum:
[tex]\[ \sqrt{100} = 10 \][/tex]
Therefore, the distance [tex]\( PQ \)[/tex] is [tex]\( 10.0 \)[/tex].
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and see you next time for more reliable information.