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In how many ways can the first 4 guests arrive at a party if 15 guests have been invited?

Note: [tex]${ }_n P _r=\frac{n!}{(n-r)!}$[/tex]

[?] ways


Sagot :

To determine the number of ways the first 4 guests can arrive at a party if 15 guests have been invited, we will use the concept of permutations. Permutations are used when the order of selection matters.

The formula for permutations is given by:
[tex]\[ {}_nP_r = \frac{n!}{(n-r)!} \][/tex]

Here, [tex]\( n \)[/tex] is the total number of items (or people, in this case), and [tex]\( r \)[/tex] is the number of items (or people) to choose.

Given:
[tex]\( n = 15 \)[/tex] (total guests)
[tex]\( r = 4 \)[/tex] (guests to choose)

Using the permutation formula:
[tex]\[ {}_{15}P_4 = \frac{15!}{(15-4)!} = \frac{15!}{11!} \][/tex]

When we expand this, we compute:
[tex]\[ \frac{15!}{11!} = \frac{15 \times 14 \times 13 \times 12 \times 11!}{11!} \][/tex]

The [tex]\(11!\)[/tex] in the numerator and denominator cancels out, leaving us with:
[tex]\[ 15 \times 14 \times 13 \times 12 \][/tex]

Multiplying these values together will give us the number of permutations:

[tex]\[ 15 \times 14 \times 13 \times 12 = 32760 \][/tex]

Thus, the number of ways the first 4 guests can arrive at the party is:
[tex]\[ 32760 \, \text{ways} \][/tex]