IDNLearn.com provides a comprehensive solution for all your question and answer needs. Ask anything and receive prompt, well-informed answers from our community of experienced experts.
Sagot :
To graph the piecewise function [tex]\( f(x) \)[/tex], we need to consider each part of the function separately and determine their values at specific points. Let's break it down step-by-step.
### 1. Understanding the Piecewise Function
The function is defined as follows:
- For [tex]\( x < 1 \)[/tex], the function is [tex]\( f(x) = 2x - 4 \)[/tex].
- For [tex]\( x \geq 1 \)[/tex], the function is [tex]\( f(x) = 1 + x \)[/tex].
### 2. Calculate Key Points
Let's find the values of the function at several points both below and above the boundary [tex]\( x = 1 \)[/tex].
#### For [tex]\( x < 1 \)[/tex]:
- When [tex]\( x = -2 \)[/tex]:
[tex]\[ f(x) = 2(-2) - 4 = -4 - 4 = -8 \][/tex]
So, the coordinate is [tex]\((-2, -8)\)[/tex].
- When [tex]\( x = 0 \)[/tex]:
[tex]\[ f(x) = 2(0) - 4 = 0 - 4 = -4 \][/tex]
So, the coordinate is [tex]\((0, -4)\)[/tex].
#### Boundary at [tex]\( x = 1 \)[/tex]:
- When [tex]\( x = 1 \)[/tex] for the first piece [tex]\( 2x - 4 \)[/tex]:
[tex]\[ f(1) = 2(1) - 4 = 2 - 4 = -2 \][/tex]
- When [tex]\( x = 1 \)[/tex] for the second piece [tex]\( 1 + x \)[/tex]:
[tex]\[ f(1) = 1 + 1 = 2 \][/tex]
So, the coordinate is [tex]\((1, 2)\)[/tex].
#### For [tex]\( x \geq 1 \)[/tex]:
- When [tex]\( x = 2 \)[/tex]:
[tex]\[ f(x) = 1 + 2 = 3 \][/tex]
So, the coordinate is [tex]\((2, 3)\)[/tex].
- When [tex]\( x = 3 \)[/tex]:
[tex]\[ f(x) = 1 + 3 = 4 \][/tex]
So, the coordinate is [tex]\((3, 4)\)[/tex].
### 3. Plotting the Points
Now we can plot these points on the graph.
- For [tex]\( x < 1 \)[/tex]:
- [tex]\((-2, -8)\)[/tex]
- [tex]\((0, -4)\)[/tex]
- For [tex]\( x \geq 1 \)[/tex]:
- [tex]\((1, 2)\)[/tex]
- [tex]\((2, 3)\)[/tex]
- [tex]\((3, 4)\)[/tex]
### 4. Drawing the Graph
- Draw a line segment through the points [tex]\((-2, -8)\)[/tex] and [tex]\((0, -4)\)[/tex] for [tex]\( x < 1 \)[/tex]. This line should approach [tex]\((1, -2)\)[/tex] but not include it since [tex]\( x = 1 \)[/tex] is not in this part.
- At [tex]\( x = 1 \)[/tex], place an open circle at [tex]\((1, -2)\)[/tex] to indicate that this point is not included in the first piece.
- For [tex]\( x \geq 1 \)[/tex], start from the point [tex]\((1, 2)\)[/tex] and draw through the points [tex]\((2, 3)\)[/tex] and [tex]\((3, 4)\)[/tex]. This includes the point [tex]\((1, 2)\)[/tex] as a closed circle because it belongs to this part of the function.
### 5. Summary
- The line segment for [tex]\( 2x - 4 \)[/tex] starts from the left extending up to but not including [tex]\((1, -2)\)[/tex] (open circle).
- The line for [tex]\( 1 + x \)[/tex] starts from [tex]\((1, 2)\)[/tex] (closed circle) and extends to the right through [tex]\((2, 3)\)[/tex] and [tex]\((3, 4)\)[/tex].
This clearly illustrates the graph of the piecewise function [tex]\( f(x) \)[/tex].
### 1. Understanding the Piecewise Function
The function is defined as follows:
- For [tex]\( x < 1 \)[/tex], the function is [tex]\( f(x) = 2x - 4 \)[/tex].
- For [tex]\( x \geq 1 \)[/tex], the function is [tex]\( f(x) = 1 + x \)[/tex].
### 2. Calculate Key Points
Let's find the values of the function at several points both below and above the boundary [tex]\( x = 1 \)[/tex].
#### For [tex]\( x < 1 \)[/tex]:
- When [tex]\( x = -2 \)[/tex]:
[tex]\[ f(x) = 2(-2) - 4 = -4 - 4 = -8 \][/tex]
So, the coordinate is [tex]\((-2, -8)\)[/tex].
- When [tex]\( x = 0 \)[/tex]:
[tex]\[ f(x) = 2(0) - 4 = 0 - 4 = -4 \][/tex]
So, the coordinate is [tex]\((0, -4)\)[/tex].
#### Boundary at [tex]\( x = 1 \)[/tex]:
- When [tex]\( x = 1 \)[/tex] for the first piece [tex]\( 2x - 4 \)[/tex]:
[tex]\[ f(1) = 2(1) - 4 = 2 - 4 = -2 \][/tex]
- When [tex]\( x = 1 \)[/tex] for the second piece [tex]\( 1 + x \)[/tex]:
[tex]\[ f(1) = 1 + 1 = 2 \][/tex]
So, the coordinate is [tex]\((1, 2)\)[/tex].
#### For [tex]\( x \geq 1 \)[/tex]:
- When [tex]\( x = 2 \)[/tex]:
[tex]\[ f(x) = 1 + 2 = 3 \][/tex]
So, the coordinate is [tex]\((2, 3)\)[/tex].
- When [tex]\( x = 3 \)[/tex]:
[tex]\[ f(x) = 1 + 3 = 4 \][/tex]
So, the coordinate is [tex]\((3, 4)\)[/tex].
### 3. Plotting the Points
Now we can plot these points on the graph.
- For [tex]\( x < 1 \)[/tex]:
- [tex]\((-2, -8)\)[/tex]
- [tex]\((0, -4)\)[/tex]
- For [tex]\( x \geq 1 \)[/tex]:
- [tex]\((1, 2)\)[/tex]
- [tex]\((2, 3)\)[/tex]
- [tex]\((3, 4)\)[/tex]
### 4. Drawing the Graph
- Draw a line segment through the points [tex]\((-2, -8)\)[/tex] and [tex]\((0, -4)\)[/tex] for [tex]\( x < 1 \)[/tex]. This line should approach [tex]\((1, -2)\)[/tex] but not include it since [tex]\( x = 1 \)[/tex] is not in this part.
- At [tex]\( x = 1 \)[/tex], place an open circle at [tex]\((1, -2)\)[/tex] to indicate that this point is not included in the first piece.
- For [tex]\( x \geq 1 \)[/tex], start from the point [tex]\((1, 2)\)[/tex] and draw through the points [tex]\((2, 3)\)[/tex] and [tex]\((3, 4)\)[/tex]. This includes the point [tex]\((1, 2)\)[/tex] as a closed circle because it belongs to this part of the function.
### 5. Summary
- The line segment for [tex]\( 2x - 4 \)[/tex] starts from the left extending up to but not including [tex]\((1, -2)\)[/tex] (open circle).
- The line for [tex]\( 1 + x \)[/tex] starts from [tex]\((1, 2)\)[/tex] (closed circle) and extends to the right through [tex]\((2, 3)\)[/tex] and [tex]\((3, 4)\)[/tex].
This clearly illustrates the graph of the piecewise function [tex]\( f(x) \)[/tex].
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.