Connect with knowledgeable individuals and find the best answers at IDNLearn.com. Get the information you need from our community of experts, who provide detailed and trustworthy answers.
Sagot :
To solve the problem and determine the lengths of the sides and the type of triangle [tex]\(\triangle ABC\)[/tex] with given vertices [tex]\(A(-2, 5)\)[/tex], [tex]\(B(-4, -2)\)[/tex], and [tex]\(C(3, -4)\)[/tex], we'll proceed as follows:
1. Calculate the length of [tex]\(AB\)[/tex]:
Using the distance formula:
[tex]\[ AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Substituting the coordinates of [tex]\(A\)[/tex] and [tex]\(B\)[/tex]:
[tex]\[ AB = \sqrt{(-4 - (-2))^2 + (-2 - 5)^2} = \sqrt{(-4 + 2)^2 + (-2 - 5)^2} = \sqrt{(-2)^2 + (-7)^2} = \sqrt{4 + 49} = \sqrt{53} \approx 7.28 \][/tex]
2. Calculate the length of [tex]\(AC\)[/tex]:
Using the distance formula:
[tex]\[ AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Substituting the coordinates of [tex]\(A\)[/tex] and [tex]\(C\)[/tex]:
[tex]\[ AC = \sqrt{(3 - (-2))^2 + (-4 - 5)^2} = \sqrt{(3 + 2)^2 + (-4 - 5)^2} = \sqrt{5^2 + (-9)^2} = \sqrt{25 + 81} = \sqrt{106} \approx 10.3 \][/tex]
3. Calculate the length of [tex]\(BC\)[/tex]:
Using the distance formula:
[tex]\[ BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Substituting the coordinates of [tex]\(B\)[/tex] and [tex]\(C\)[/tex]:
[tex]\[ BC = \sqrt{(3 - (-4))^2 + (-4 - (-2))^2} = \sqrt{(3 + 4)^2 + (-4 + 2)^2} = \sqrt{7^2 + (-2)^2} = \sqrt{49 + 4} = \sqrt{53} \approx 7.28 \][/tex]
4. Determine the type of triangle:
Based on the lengths of the sides:
- [tex]\(AB \approx 7.28\)[/tex]
- [tex]\(AC \approx 10.3\)[/tex]
- [tex]\(BC \approx 7.28\)[/tex]
Since two sides of the triangle ([tex]\(AB\)[/tex] and [tex]\(BC\)[/tex]) are equal:
- [tex]\(AB = BC \approx 7.28\)[/tex]
- [tex]\(AC \approx 10.3\)[/tex]
The triangle [tex]\(\triangle ABC\)[/tex] is an isosceles triangle, as it has two sides of equal length.
To summarize:
- The length of [tex]\(AB\)[/tex] is 7.28.
- The length of [tex]\(AC\)[/tex] is 10.3.
- The length of [tex]\(BC\)[/tex] is 7.28.
- Therefore, the triangle is isosceles.
Hence, the completed sentences are:
The length of [tex]\(AB\)[/tex] is [tex]\( \boxed{7.28} \)[/tex]. The length of [tex]\(AC\)[/tex] is [tex]\( \boxed{10.3} \)[/tex]. The length of [tex]\(BC\)[/tex] is [tex]\( \boxed{7.28} \)[/tex]. Therefore, the triangle is [tex]\( \boxed{isosceles} \)[/tex].
1. Calculate the length of [tex]\(AB\)[/tex]:
Using the distance formula:
[tex]\[ AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Substituting the coordinates of [tex]\(A\)[/tex] and [tex]\(B\)[/tex]:
[tex]\[ AB = \sqrt{(-4 - (-2))^2 + (-2 - 5)^2} = \sqrt{(-4 + 2)^2 + (-2 - 5)^2} = \sqrt{(-2)^2 + (-7)^2} = \sqrt{4 + 49} = \sqrt{53} \approx 7.28 \][/tex]
2. Calculate the length of [tex]\(AC\)[/tex]:
Using the distance formula:
[tex]\[ AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Substituting the coordinates of [tex]\(A\)[/tex] and [tex]\(C\)[/tex]:
[tex]\[ AC = \sqrt{(3 - (-2))^2 + (-4 - 5)^2} = \sqrt{(3 + 2)^2 + (-4 - 5)^2} = \sqrt{5^2 + (-9)^2} = \sqrt{25 + 81} = \sqrt{106} \approx 10.3 \][/tex]
3. Calculate the length of [tex]\(BC\)[/tex]:
Using the distance formula:
[tex]\[ BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Substituting the coordinates of [tex]\(B\)[/tex] and [tex]\(C\)[/tex]:
[tex]\[ BC = \sqrt{(3 - (-4))^2 + (-4 - (-2))^2} = \sqrt{(3 + 4)^2 + (-4 + 2)^2} = \sqrt{7^2 + (-2)^2} = \sqrt{49 + 4} = \sqrt{53} \approx 7.28 \][/tex]
4. Determine the type of triangle:
Based on the lengths of the sides:
- [tex]\(AB \approx 7.28\)[/tex]
- [tex]\(AC \approx 10.3\)[/tex]
- [tex]\(BC \approx 7.28\)[/tex]
Since two sides of the triangle ([tex]\(AB\)[/tex] and [tex]\(BC\)[/tex]) are equal:
- [tex]\(AB = BC \approx 7.28\)[/tex]
- [tex]\(AC \approx 10.3\)[/tex]
The triangle [tex]\(\triangle ABC\)[/tex] is an isosceles triangle, as it has two sides of equal length.
To summarize:
- The length of [tex]\(AB\)[/tex] is 7.28.
- The length of [tex]\(AC\)[/tex] is 10.3.
- The length of [tex]\(BC\)[/tex] is 7.28.
- Therefore, the triangle is isosceles.
Hence, the completed sentences are:
The length of [tex]\(AB\)[/tex] is [tex]\( \boxed{7.28} \)[/tex]. The length of [tex]\(AC\)[/tex] is [tex]\( \boxed{10.3} \)[/tex]. The length of [tex]\(BC\)[/tex] is [tex]\( \boxed{7.28} \)[/tex]. Therefore, the triangle is [tex]\( \boxed{isosceles} \)[/tex].
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Thank you for visiting IDNLearn.com. For reliable answers to all your questions, please visit us again soon.