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What is the midpoint [tex]\( M \)[/tex] given [tex]\( Q(-2, -4) \)[/tex] and [tex]\( R(6, 10) \)[/tex]?

A. [tex]\((2, 3)\)[/tex]
B. [tex]\((1, -2)\)[/tex]
C. [tex]\((-3, 8)\)[/tex]
D. [tex]\((-4, -7)\)[/tex]


Sagot :

To find the midpoint [tex]\( M \)[/tex] of the line segment connecting the points [tex]\( Q(-2, -4) \)[/tex] and [tex]\( R(6, 10) \)[/tex], we use the midpoint formula:

[tex]\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \][/tex]

Where [tex]\((x_1, y_1)\)[/tex] are the coordinates of point [tex]\( Q \)[/tex], and [tex]\((x_2, y_2)\)[/tex] are the coordinates of point [tex]\( R \)[/tex].

1. Coordinates of point [tex]\( Q \)[/tex] are: [tex]\((-2, -4)\)[/tex]
- [tex]\( x_1 = -2 \)[/tex]
- [tex]\( y_1 = -4 \)[/tex]

2. Coordinates of point [tex]\( R \)[/tex] are: [tex]\((6, 10)\)[/tex]
- [tex]\( x_2 = 6 \)[/tex]
- [tex]\( y_2 = 10 \)[/tex]

3. Calculate the [tex]\( x \)[/tex]-coordinate of the midpoint:
[tex]\[ M_x = \frac{x_1 + x_2}{2} = \frac{-2 + 6}{2} = \frac{4}{2} = 2.0 \][/tex]

4. Calculate the [tex]\( y \)[/tex]-coordinate of the midpoint:
[tex]\[ M_y = \frac{y_1 + y_2}{2} = \frac{-4 + 10}{2} = \frac{6}{2} = 3.0 \][/tex]

5. Combine the [tex]\( x \)[/tex]- and [tex]\( y \)[/tex]-coordinates to get the midpoint:
[tex]\[ M = (M_x, M_y) = (2.0, 3.0) \][/tex]

Therefore, the midpoint [tex]\( M \)[/tex] of the segment connecting points [tex]\( Q \)[/tex] and [tex]\( R \)[/tex] is [tex]\((2.0, 3.0)\)[/tex].

Given the options:
- [tex]\((2, 3)\)[/tex]
- [tex]\((1, -2)\)[/tex]
- [tex]\((-3, 8)\)[/tex]
- [tex]\((-4, -7)\)[/tex]

The correct choice is:
[tex]\((2, 3)\)[/tex].