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Solve the problem.

Find the break-even point for the given cost and revenue equations. Round to the nearest whole unit.

[tex]\[
\begin{array}{l}
C = 94n + 534,000 \\
R = 168n
\end{array}
\][/tex]

A. 74

B. 2038

C. 262

D. 7216


Sagot :

To find the break-even point for the given cost and revenue equations, we need to determine the number of units [tex]\( n \)[/tex] at which the cost equals the revenue. The given equations are:

[tex]\[ \begin{array}{l} C = 94n + 534,000 \\ R = 168 n \end{array} \][/tex]

The break-even point is where Cost [tex]\( C \)[/tex] equals Revenue [tex]\( R \)[/tex]. Therefore, we set the equations equal to each other:

[tex]\[ 94n + 534,000 = 168n \][/tex]

Next, we need to solve for [tex]\( n \)[/tex]. To do this, we first isolate [tex]\( n \)[/tex] by moving all terms involving [tex]\( n \)[/tex] to one side of the equation. We can achieve this by subtracting [tex]\( 94n \)[/tex] from both sides:

[tex]\[ 534,000 = 168n - 94n \][/tex]

Simplify the right side of the equation:

[tex]\[ 534,000 = 74n \][/tex]

Now, solve for [tex]\( n \)[/tex] by dividing both sides of the equation by 74:

[tex]\[ n = \frac{534,000}{74} \][/tex]

Perform the division to find the value of [tex]\( n \)[/tex]:

[tex]\[ n = 7216.216216216216 \][/tex]

Since we are asked to round to the nearest whole unit, we round 7216.216216216216 to:

[tex]\[ n \approx 7216 \][/tex]

Therefore, the break-even point is:

[tex]\[ d. 7216 \][/tex]
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