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Identify the [tex]$y$[/tex]-intercept of [tex]$y = x^2 + 9$[/tex].

A. [tex][tex]$(0, -9)$[/tex][/tex]
B. [tex]$(0, 3)$[/tex]
C. [tex]$(0, -3)$[/tex]
D. [tex][tex]$(0, 9)$[/tex][/tex]


Sagot :

To identify the [tex]$y$[/tex]-intercept of the equation [tex]\( y = x^2 + 9 \)[/tex], we need to understand what a [tex]$y$[/tex]-intercept is. The [tex]$y$[/tex]-intercept is the point where the graph of the equation crosses the [tex]$y$[/tex]-axis. At this point, the value of [tex]$x$[/tex] is 0.

Here's a step-by-step solution:

1. Start with the given equation: [tex]\( y = x^2 + 9 \)[/tex].
2. Substitute [tex]\( x = 0 \)[/tex] into the equation to find the [tex]$y$[/tex]-intercept:
[tex]\[ y = (0)^2 + 9 \][/tex]
3. Calculate the value of [tex]\( y \)[/tex]:
[tex]\[ y = 0 + 9 \][/tex]
[tex]\[ y = 9 \][/tex]
4. Identify the [tex]$y$[/tex]-intercept: Since [tex]\( x = 0 \)[/tex] and [tex]\( y = 9 \)[/tex], the [tex]$y$[/tex]-intercept is at the point [tex]\( (0, 9) \)[/tex].

Therefore, the correct answer is:

D. [tex]\( (0, 9) \)[/tex]