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Sagot :
Let's solve the equation:
[tex]\[ \ln(2x + 4) = \ln(x + 3) \][/tex]
Since the natural logarithm function [tex]\(\ln\)[/tex] is one-to-one, we can equate the arguments of the logarithms:
[tex]\[ 2x + 4 = x + 3 \][/tex]
Next, we need to solve for [tex]\(x\)[/tex]:
1. Subtract [tex]\(x\)[/tex] from both sides:
[tex]\[ 2x + 4 - x = x + 3 - x \][/tex]
This simplifies to:
[tex]\[ x + 4 = 3 \][/tex]
2. Subtract 4 from both sides to isolate [tex]\(x\)[/tex]:
[tex]\[ x + 4 - 4 = 3 - 4 \][/tex]
This simplifies to:
[tex]\[ x = -1 \][/tex]
So, the solution to the equation [tex]\(\ln(2x + 4) = \ln(x + 3)\)[/tex] is:
[tex]\[ x = -1 \][/tex]
Hence, the correct answer is:
C. [tex]\(x = -1\)[/tex]
[tex]\[ \ln(2x + 4) = \ln(x + 3) \][/tex]
Since the natural logarithm function [tex]\(\ln\)[/tex] is one-to-one, we can equate the arguments of the logarithms:
[tex]\[ 2x + 4 = x + 3 \][/tex]
Next, we need to solve for [tex]\(x\)[/tex]:
1. Subtract [tex]\(x\)[/tex] from both sides:
[tex]\[ 2x + 4 - x = x + 3 - x \][/tex]
This simplifies to:
[tex]\[ x + 4 = 3 \][/tex]
2. Subtract 4 from both sides to isolate [tex]\(x\)[/tex]:
[tex]\[ x + 4 - 4 = 3 - 4 \][/tex]
This simplifies to:
[tex]\[ x = -1 \][/tex]
So, the solution to the equation [tex]\(\ln(2x + 4) = \ln(x + 3)\)[/tex] is:
[tex]\[ x = -1 \][/tex]
Hence, the correct answer is:
C. [tex]\(x = -1\)[/tex]
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