To determine whether the statement "A positive magnification means the image is inverted compared to the object" is true or false, let's review some fundamental concepts of optics, particularly pertaining to magnification.
Magnification refers to how much larger or smaller the image is compared to the object. It is calculated using the formula:
[tex]\[ M = \frac{h_i}{h_o} = -\frac{d_i}{d_o} \][/tex]
where:
- [tex]\( M \)[/tex] is the magnification.
- [tex]\( h_i \)[/tex] is the height of the image.
- [tex]\( h_o \)[/tex] is the height of the object.
- [tex]\( d_i \)[/tex] is the distance of the image from the lens or mirror.
- [tex]\( d_o \)[/tex] is the distance of the object from the lens or mirror.
In terms of interpreting magnification:
- If the magnification [tex]\( M \)[/tex] is positive, the image is upright relative to the object.
- If the magnification [tex]\( M \)[/tex] is negative, the image is inverted relative to the object.
Given this understanding:
- Positive magnification [tex]\( M > 0 \)[/tex] --> image is upright.
- Negative magnification [tex]\( M < 0 \)[/tex] --> image is inverted.
The statement in question is: "A positive magnification means the image is inverted compared to the object."
Based on the definitions and explanations provided:
- A positive magnification should indicate that the image is upright, not inverted.
Therefore, the statement "A positive magnification means the image is inverted compared to the object" is:
False
So, the correct answer is:
False
