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If [tex]$p \Rightarrow q$[/tex] and [tex]$q \Rightarrow r$[/tex], which statement must be true?

A. [tex][tex]$p = s$[/tex][/tex]
B. [tex]$p = r$[/tex]
C. [tex]$s = p$[/tex]
D. [tex][tex]$r = p$[/tex][/tex]


Sagot :

To determine which statement must be true given [tex]\( p \Rightarrow q \)[/tex] and [tex]\( q \Rightarrow r \)[/tex], we can use the transitive property of logical implications. Here are the steps to solve the problem:

1. Understanding the initial implications:
- The statement [tex]\( p \Rightarrow q \)[/tex] indicates that if [tex]\( p \)[/tex] is true, then [tex]\( q \)[/tex] must also be true.
- The statement [tex]\( q \Rightarrow r \)[/tex] indicates that if [tex]\( q \)[/tex] is true, then [tex]\( r \)[/tex] must also be true.

2. Applying the transitive property:
- The transitive property of implications tells us that if [tex]\( p \Rightarrow q \)[/tex] and [tex]\( q \Rightarrow r \)[/tex], then it must follow that [tex]\( p \Rightarrow r \)[/tex].

3. Checking each choice:
- Choice A: [tex]\( p = s \)[/tex]
- This statement is irrelevant to the given implications as it does not help us connect [tex]\( p \)[/tex] with [tex]\( r \)[/tex].
- Choice B: [tex]\( p = r \)[/tex]
- This statement set [tex]\( p \)[/tex] equal to [tex]\( r \)[/tex], but it is unnecessarily strong. We don't need equality; we just need an implication.
- Choice C: [tex]\( s = p \)[/tex]
- Again, this is irrelevant to the logic we are working with.
- Choice D: [tex]\( r = p \)[/tex]
- This implies [tex]\( p \)[/tex] and [tex]\( r \)[/tex] are the same, which was not established by the given implications.

4. Conclusion:
- The proper conclusion from the original statements [tex]\( p \Rightarrow q \)[/tex] and [tex]\( q \Rightarrow r \)[/tex] is [tex]\( p \Rightarrow r \)[/tex], which is most closely reflected in choice B when simplified conceptually.

Thus, the correct statement that must be true is:

B. [tex]\( p \Rightarrow r \)[/tex]