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Amari is standing 50 feet from the base of a building. From where he stands, the angle formed between the top of the building and the ground at his feet is [tex]$60^{\circ}$[/tex].

How tall is the building?

A. 50 ft
B. [tex]\frac{50 \sqrt{3}}{3}[/tex] ft
C. [tex]50 \sqrt{3}[/tex] ft
D. 100 ft


Sagot :

To determine the height of the building when Amari is standing 50 feet away from its base, and the angle of elevation to the top of the building is [tex]\( 60^\circ \)[/tex], we can use trigonometry, specifically the tangent function. The tangent of an angle in a right triangle is the ratio of the opposite side (the height [tex]\( h \)[/tex] of the building in this case) to the adjacent side (the distance [tex]\( d \)[/tex] from Amari to the base).

The steps to solve the problem are as follows:

1. Identify the known values:
- Distance from Amari to the building's base, [tex]\( d = 50 \)[/tex] feet.
- Angle of elevation, [tex]\( \theta = 60^\circ \)[/tex].

2. Use the tangent function:
The tangent of the angle of elevation is given by:
[tex]\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{h}{d} \][/tex]

3. Plug in the known values:
[tex]\[ \tan(60^\circ) = \frac{h}{50} \][/tex]

4. Use the value of [tex]\(\tan(60^\circ)\)[/tex]:
We know that [tex]\(\tan(60^\circ) = \sqrt{3}\)[/tex].

5. Set up the equation:
[tex]\[ \sqrt{3} = \frac{h}{50} \][/tex]

6. Solve for the height [tex]\( h \)[/tex]:
Multiply both sides of the equation by 50:
[tex]\[ h = 50 \times \sqrt{3} \][/tex]

7. Calculate the numeric value:
[tex]\[ \sqrt{3} \approx 1.732 \][/tex]
[tex]\[ h = 50 \times 1.732 = 86.602 \text{ feet} \][/tex]

Therefore, the height of the building is approximately [tex]\( 86.60 \)[/tex] feet, matching one of our multiple choice options more concisely:
[tex]\[ 50 \sqrt{3} \text{ feet} \][/tex]

So, the correct answer is [tex]\( 50\sqrt{3} \text{ \ feet} \)[/tex].