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To solve the compound inequality [tex]\(5x - 7 \geq 8\)[/tex] or [tex]\(4x + 4 < -20\)[/tex], we need to solve each inequality separately and then combine the solutions using the logical "or."
### Step 1: Solve [tex]\(5x - 7 \geq 8\)[/tex]
1. Isolate [tex]\(x\)[/tex]:
[tex]\[ 5x - 7 \geq 8 \][/tex]
2. Add 7 to both sides:
[tex]\[ 5x \geq 15 \][/tex]
3. Divide both sides by 5:
[tex]\[ x \geq 3 \][/tex]
### Step 2: Solve [tex]\(4x + 4 < -20\)[/tex]
1. Isolate [tex]\(x\)[/tex]:
[tex]\[ 4x + 4 < -20 \][/tex]
2. Subtract 4 from both sides:
[tex]\[ 4x < -24 \][/tex]
3. Divide both sides by 4:
[tex]\[ x < -6 \][/tex]
### Step 3: Combine the solutions
The solutions to the inequalities are:
1. [tex]\(x \geq 3\)[/tex] from the first inequality.
2. [tex]\(x < -6\)[/tex] from the second inequality.
Combining these, we get [tex]\(x \geq 3\)[/tex] or [tex]\(x < -6\)[/tex].
Thus, the correct answer is:
a. [tex]\(x \geq 3\)[/tex] or [tex]\(x < -6\)[/tex].
### Step 1: Solve [tex]\(5x - 7 \geq 8\)[/tex]
1. Isolate [tex]\(x\)[/tex]:
[tex]\[ 5x - 7 \geq 8 \][/tex]
2. Add 7 to both sides:
[tex]\[ 5x \geq 15 \][/tex]
3. Divide both sides by 5:
[tex]\[ x \geq 3 \][/tex]
### Step 2: Solve [tex]\(4x + 4 < -20\)[/tex]
1. Isolate [tex]\(x\)[/tex]:
[tex]\[ 4x + 4 < -20 \][/tex]
2. Subtract 4 from both sides:
[tex]\[ 4x < -24 \][/tex]
3. Divide both sides by 4:
[tex]\[ x < -6 \][/tex]
### Step 3: Combine the solutions
The solutions to the inequalities are:
1. [tex]\(x \geq 3\)[/tex] from the first inequality.
2. [tex]\(x < -6\)[/tex] from the second inequality.
Combining these, we get [tex]\(x \geq 3\)[/tex] or [tex]\(x < -6\)[/tex].
Thus, the correct answer is:
a. [tex]\(x \geq 3\)[/tex] or [tex]\(x < -6\)[/tex].
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