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Sagot :
To solve the compound inequality [tex]\( -11 < 2x + 5 < 17 \)[/tex], we need to break it down into two separate inequalities and solve each one step-by-step.
1. Solve the first inequality:
[tex]\[ -11 < 2x + 5 \][/tex]
- Begin by isolating [tex]\( 2x \)[/tex] by subtracting 5 from both sides:
[tex]\[ -11 - 5 < 2x \][/tex]
Simplifying the left side:
[tex]\[ -16 < 2x \][/tex]
- Next, divide both sides by 2 to solve for [tex]\( x \)[/tex]:
[tex]\[ \frac{-16}{2} < x \][/tex]
Simplifying:
[tex]\[ -8 < x \][/tex]
2. Solve the second inequality:
[tex]\[ 2x + 5 < 17 \][/tex]
- Subtract 5 from both sides:
[tex]\[ 2x < 17 - 5 \][/tex]
Simplifying the right side:
[tex]\[ 2x < 12 \][/tex]
- Next, divide both sides by 2 to solve for [tex]\( x \)[/tex]:
[tex]\[ \frac{12}{2} > x \][/tex]
Simplifying:
[tex]\[ x < 6 \][/tex]
3. Combine the two inequalities:
- From step 1, we have [tex]\( -8 < x \)[/tex]
- From step 2, we have [tex]\( x < 6 \)[/tex]
Combining these results, we get the compound inequality:
[tex]\[ -8 < x < 6 \][/tex]
So, the correct answer is:
b. [tex]\( -8 < x < 6 \)[/tex]
1. Solve the first inequality:
[tex]\[ -11 < 2x + 5 \][/tex]
- Begin by isolating [tex]\( 2x \)[/tex] by subtracting 5 from both sides:
[tex]\[ -11 - 5 < 2x \][/tex]
Simplifying the left side:
[tex]\[ -16 < 2x \][/tex]
- Next, divide both sides by 2 to solve for [tex]\( x \)[/tex]:
[tex]\[ \frac{-16}{2} < x \][/tex]
Simplifying:
[tex]\[ -8 < x \][/tex]
2. Solve the second inequality:
[tex]\[ 2x + 5 < 17 \][/tex]
- Subtract 5 from both sides:
[tex]\[ 2x < 17 - 5 \][/tex]
Simplifying the right side:
[tex]\[ 2x < 12 \][/tex]
- Next, divide both sides by 2 to solve for [tex]\( x \)[/tex]:
[tex]\[ \frac{12}{2} > x \][/tex]
Simplifying:
[tex]\[ x < 6 \][/tex]
3. Combine the two inequalities:
- From step 1, we have [tex]\( -8 < x \)[/tex]
- From step 2, we have [tex]\( x < 6 \)[/tex]
Combining these results, we get the compound inequality:
[tex]\[ -8 < x < 6 \][/tex]
So, the correct answer is:
b. [tex]\( -8 < x < 6 \)[/tex]
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