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Simplify [tex]$\frac{1}{2-\sqrt{2}}$[/tex] by rationalizing the denominator.

A. [tex]$\frac{2+\sqrt{2}}{2}$[/tex]
B. [tex][tex]$\frac{2+\sqrt{2}}{6}$[/tex][/tex]
C. [tex]$\frac{2-\sqrt{2}}{2}$[/tex]
D. [tex]$\frac{2-\sqrt{2}}{6}$[/tex]


Sagot :

To simplify the expression [tex]\(\frac{1}{2-\sqrt{2}}\)[/tex] by rationalizing the denominator, we follow these steps:

1. Write down the expression:
[tex]\[\frac{1}{2-\sqrt{2}}\][/tex]

2. Identify the conjugate of the denominator. The conjugate of [tex]\(2 - \sqrt{2}\)[/tex] is [tex]\(2 + \sqrt{2}\)[/tex].

3. Multiply the numerator and the denominator by the conjugate of the denominator to eliminate the square root:
[tex]\[ \frac{1 \cdot (2 + \sqrt{2})}{(2 - \sqrt{2}) \cdot (2 + \sqrt{2})} \][/tex]

4. Simplify the numerator:
[tex]\[ 1 \cdot (2 + \sqrt{2}) = 2 + \sqrt{2} \][/tex]

5. Simplify the denominator using the difference of squares formula [tex]\( (a - b)(a + b) = a^2 - b^2 \)[/tex]:
[tex]\[ (2 - \sqrt{2})(2 + \sqrt{2}) = 2^2 - (\sqrt{2})^2 = 4 - 2 = 2 \][/tex]

6. Combine the simplified numerator and denominator:
[tex]\[ \frac{2 + \sqrt{2}}{2} \][/tex]

Thus, the expression [tex]\(\frac{1}{2-\sqrt{2}}\)[/tex] simplifies to:
[tex]\[ \frac{2 + \sqrt{2}}{2} \][/tex]

So, the correct answer is:
[tex]\[ \boxed{\frac{2+\sqrt{2}}{2}} \][/tex]