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Evaluate the expression when [tex]$m = 4$[/tex] and [tex]$n = 2$[/tex].

[tex]
3n + 2(2n + m) + m^2 = [?]
[/tex]

Sagot :

GinnyAnsweridn
Certainly! Let's evaluate the given expression step-by-step when [tex]\( m = 4 \)[/tex] and [tex]\( n = 2 \)[/tex].

The expression to evaluate is:
[tex]\[ 3n + 2(2n + m) + m^2 \][/tex]

1. Substitute [tex]\( n = 2 \)[/tex] and [tex]\( m = 4 \)[/tex] into the expression:

[tex]\[ 3(2) + 2(2(2) + 4) + 4^2 \][/tex]

2. Compute the first part of the expression [tex]\( 3n \)[/tex]:

[tex]\[ 3(2) = 6 \][/tex]

3. Compute the inside of the second part [tex]\( 2(2n + m) \)[/tex]:

- First, compute [tex]\( 2n \)[/tex]:
[tex]\[ 2(2) = 4 \][/tex]
- Then add [tex]\( m \)[/tex]:
[tex]\[ 4 + 4 = 8 \][/tex]
- Multiply by 2:
[tex]\[ 2(8) = 16 \][/tex]

4. Compute the third part of the expression [tex]\( m^2 \)[/tex]:

[tex]\[ 4^2 = 16 \][/tex]

5. Add all parts together:

- First part:
[tex]\[ 6 \][/tex]
- Second part:
[tex]\[ 16 \][/tex]
- Third part:
[tex]\[ 16 \][/tex]
- Sum them:
[tex]\[ 6 + 16 + 16 = 38 \][/tex]

So, the evaluated result for [tex]\( 3n + 2(2n + m) + m^2 \)[/tex] when [tex]\( m = 4 \)[/tex] and [tex]\( n = 2 \)[/tex] is:
[tex]\[ 38 \][/tex]
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