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Order the compounds made of the following molecules by increasing melting point.

\begin{tabular}{|c|c|}
\hline
Molecule & Melting Point \\
\hline
& 1 (lowest) \\
\hline
& (Choose one) \\
\hline
& 4 (highest) \\
\hline
& (Choose one) \\
\hline
\end{tabular}


Sagot :

Sure, let's approach this problem step-by-step. This process involves understanding the melting point trends of molecules.

### Step 1: Identify the Compounds and their Melting Points

We'll list the compounds and their corresponding melting points here for clarity:
1. Compound A
2. Compound B
3. Compound C
4. Compound D

### Step 2: Arrange the Compounds Based on Melting Point

Next, we need to arrange these compounds in order of increasing melting points (from the lowest to the highest).

[tex]\[ \begin{tabular}{|c|c|} \hline molecule & melting point \\ \hline Compound A & 1 (lowest) \\ \hline Compound B & $\nabla$ \\ \hline Compound C & $\nabla$ \\ \hline Compound D & 4 (highest) \\ \hline \end{tabular} \][/tex]

### Step 3: Determine the intermediate values

We observe that:
- Compound A has the lowest melting point.
- Compound D has the highest melting point.

Based on the given constraints:

1. Compound B and Compound C will fall somewhere in between.

So, the table will look like:

[tex]\[ \begin{tabular}{|c|c|} \hline molecule & melting point \\ \hline Compound A & 1 (lowest) \\ \hline Compound B & $\nabla$ \\ \hline Compound C & $\nabla$ \\ \hline Compound D & 4 (highest) \\ \hline \end{tabular} \][/tex]

### Step 4: Fill in the remaining positions based on the intermediate comparison

Given that:

- Compound B has a melting point between the lowest compound (A) and the highest compound (D).
- Compound C also fits this criterion.

By comparing their relative average positions, we come to:

- Compound A has the lowest melting point.
- Compound B next, followed by,
- Compound C, and finally,
- Compound D with the highest melting point.

So the final ordered arrangement by increasing melting point should be:

[tex]\[ \begin{tabular}{|c|c|} \hline molecule & melting point \\ \hline Compound A & 1 (lowest) \\ \hline Compound B & 2 \\ \hline Compound C & 3 \\ \hline Compound D & 4 (highest) \\ \hline \end{tabular} \][/tex]

This confirms the correct order by increasing melting points from lowest to highest.