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Solve for [tex]\( x \)[/tex]:
[tex]\[ 3x = 6x - 2 \][/tex]

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[tex]\[ \large{1 \; 3 \; 4 \div 5 \; 4 \; 9} \][/tex]
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Response:
[tex]\[ \large{1 \; 3 \; 4 \div 5 \; 4 \; 9} \][/tex]


Sagot :

To solve the division problem [tex]\(549 \div 134\)[/tex] step-by-step:

1. Start with the division setup:
We have the dividend [tex]\(549\)[/tex] and the divisor [tex]\(134\)[/tex]. We need to find how many times [tex]\(134\)[/tex] can be subtracted from [tex]\(549\)[/tex] without going negative, which is essentially finding the quotient and the remainder.

2. Determine the Quotient:
- Check how many whole times [tex]\(134\)[/tex] can fit into [tex]\(549\)[/tex].
- Considering [tex]\(134 \times 4 = 536\)[/tex] is the highest multiple of [tex]\(134\)[/tex] that does not exceed [tex]\(549\)[/tex], the quotient is [tex]\(4\)[/tex].

3. Multiply and Subtract:
- Multiply [tex]\(134 \times 4 = 536\)[/tex].
- Subtract this product from the dividend [tex]\(549\)[/tex]:
[tex]\[ 549 - 536 = 13 \][/tex]

4. Conclusion:
- The quotient is [tex]\(4\)[/tex].
- The remainder is [tex]\(13\)[/tex].

Thus, the result of [tex]\(549 \div 134\)[/tex] is a quotient of [tex]\(4\)[/tex] with a remainder of [tex]\(13\)[/tex].

So, the division of [tex]\(549\)[/tex] by [tex]\(134\)[/tex] yields:
[tex]\[ 549 \div 134 = 4 \text{ remainder } 13 \][/tex]
or in another form:
[tex]\[ 549 = 134 \times 4 + 13 \][/tex]
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