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Following is a sample of five matched pairs.

\begin{tabular}{lrrrrr}
\hline
Sample 1 & 18 & 11 & 19 & 20 & 21 \\
Sample 2 & 19 & 11 & 19 & 20 & 16 \\
\hline
\end{tabular}

Let [tex]$\mu_1$[/tex] and [tex]$\mu_2$[/tex] represent the population means, and let [tex]$\mu_{ d }=\mu_1-\mu_2$[/tex]. A test will be made of the hypotheses [tex][tex]$H_0: \mu_{ d }=0$[/tex][/tex] versus [tex]$H_1: \mu_{ d }\ \textgreater \ 0$[/tex]. Compute the test statistic.

A) 0.335
B) 1.158
C) 0.749
D) 0.358


Sagot :

To compute the test statistic for comparing two matched pairs in hypothesis testing, we follow several steps:

1. Determine the differences between each pair:
Given pairs from the samples are:
- [tex]\( (18, 19) \)[/tex]
- [tex]\( (11, 11) \)[/tex]
- [tex]\( (19, 19) \)[/tex]
- [tex]\( (20, 20) \)[/tex]
- [tex]\( (21, 16) \)[/tex]

The differences,
[tex]\[ d_i = \text{Sample 1} - \text{Sample 2} \][/tex]
are as follows:
[tex]\[ d = [18-19, 11-11, 19-19, 20-20, 21-16] = [-1, 0, 0, 0, 5] \][/tex]

2. Calculate the mean of the differences:
The mean difference, [tex]\( \bar{d} \)[/tex], is calculated by summing up the differences and dividing by the number of differences [tex]\( n \)[/tex]:
[tex]\[ \bar{d} = \frac{-1 + 0 + 0 + 0 + 5}{5} = \frac{4}{5} = 0.8 \][/tex]

3. Calculate the standard deviation of the differences:
The standard deviation of the differences, [tex]\( s_d \)[/tex], is:
[tex]\[ s_d = 2.3874672772626644 \][/tex]

4. Calculate the test statistic:
The test statistic for a paired t-test is calculated using:
[tex]\[ t = \frac{\bar{d}}{s_d / \sqrt{n}} \][/tex]
where [tex]\( n = 5 \)[/tex] is the number of pairs.

Substitute the values:
[tex]\[ t = \frac{0.8}{2.3874672772626644 / \sqrt{5}} = 0.7492686492653552 \][/tex]

Given the choices, the correct test statistic is:
C) 0.749