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Sagot :
To solve the inequality [tex]\(|7x + 3| < 11\)[/tex], we need to consider the definition of absolute value. The absolute value inequality [tex]\(|A| < B\)[/tex] is equivalent to [tex]\(-B < A < B\)[/tex]. Thus, we can rewrite the given inequality without the absolute value as follows:
[tex]\[ -11 < 7x + 3 < 11 \][/tex]
We will solve this compound inequality step by step.
1. Subtract 3 from all parts of the inequality:
[tex]\[ -11 - 3 < 7x + 3 - 3 < 11 - 3 \][/tex]
This simplifies to:
[tex]\[ -14 < 7x < 8 \][/tex]
2. Divide all parts of the inequality by 7 to solve for [tex]\(x\)[/tex]:
[tex]\[ \frac{-14}{7} < \frac{7x}{7} < \frac{8}{7} \][/tex]
This simplifies to:
[tex]\[ -2 < x < \frac{8}{7} \][/tex]
Therefore, the solution to the inequality [tex]\(|7x + 3| < 11\)[/tex] is:
[tex]\[ -2 < x < \frac{8}{7} \][/tex]
[tex]\[ -11 < 7x + 3 < 11 \][/tex]
We will solve this compound inequality step by step.
1. Subtract 3 from all parts of the inequality:
[tex]\[ -11 - 3 < 7x + 3 - 3 < 11 - 3 \][/tex]
This simplifies to:
[tex]\[ -14 < 7x < 8 \][/tex]
2. Divide all parts of the inequality by 7 to solve for [tex]\(x\)[/tex]:
[tex]\[ \frac{-14}{7} < \frac{7x}{7} < \frac{8}{7} \][/tex]
This simplifies to:
[tex]\[ -2 < x < \frac{8}{7} \][/tex]
Therefore, the solution to the inequality [tex]\(|7x + 3| < 11\)[/tex] is:
[tex]\[ -2 < x < \frac{8}{7} \][/tex]
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