Get personalized answers to your specific questions with IDNLearn.com. Our experts provide prompt and accurate answers to help you make informed decisions on any topic.
Sagot :
Sure, let's analyze and simplify the given expression step-by-step.
We need to determine the product of:
[tex]\[ \frac{2a - 7}{a} \times \frac{3a^2}{2a^2 - 11a + 14} \][/tex]
### Step 1: Factorize and Simplify
1. Identify the factorization of the denominator [tex]\(2a^2 - 11a + 14\)[/tex].
To factorize [tex]\(2a^2 - 11a + 14\)[/tex], we look for two numbers whose product is [tex]\(2 \times 14 = 28\)[/tex] and whose sum is [tex]\(-11\)[/tex]. These numbers are [tex]\(-4\)[/tex] and [tex]\(-7\)[/tex].
Split the middle term:
[tex]\[ 2a^2 - 4a - 7a + 14 \][/tex]
Group the terms:
[tex]\[ (2a^2 - 4a) - (7a - 14) \][/tex]
Factor each group:
[tex]\[ 2a(a - 2) - 7(a - 2) \][/tex]
Factor out the common term [tex]\((a - 2)\)[/tex]:
[tex]\[ (2a - 7)(a - 2) \][/tex]
So, [tex]\( 2a^2 - 11a + 14 = (2a - 7)(a - 2) \)[/tex].
### Step 2: Rewrite the Expression
Rewrite the original product using the factorization:
[tex]\[ \frac{2a - 7}{a} \times \frac{3a^2}{(2a - 7)(a - 2)} \][/tex]
### Step 3: Simplify the Expression
Now, cancel common factors:
The [tex]\((2a - 7)\)[/tex] term in the numerator and denominator cancel out:
[tex]\[ \frac{2a - 7}{a} \times \frac{3a^2}{(2a - 7)(a - 2)} = \frac{1}{a} \times \frac{3a^2}{a - 2} = \frac{3a^2}{a(a - 2)} \][/tex]
Further simplifying:
[tex]\[ \frac{3a^2}{a(a - 2)} = \frac{3a}{a - 2} \][/tex]
### Step 4: Identify the Correct Option
The simplified product of:
[tex]\[ \frac{2a - 7}{a} \times \frac{3a^2}{(2a - 7)(a - 2)} \][/tex]
is:
[tex]\[ \frac{3a}{a - 2} \][/tex]
So, the answer is:
[tex]\[ \frac{3a}{a - 2} \][/tex]
We need to determine the product of:
[tex]\[ \frac{2a - 7}{a} \times \frac{3a^2}{2a^2 - 11a + 14} \][/tex]
### Step 1: Factorize and Simplify
1. Identify the factorization of the denominator [tex]\(2a^2 - 11a + 14\)[/tex].
To factorize [tex]\(2a^2 - 11a + 14\)[/tex], we look for two numbers whose product is [tex]\(2 \times 14 = 28\)[/tex] and whose sum is [tex]\(-11\)[/tex]. These numbers are [tex]\(-4\)[/tex] and [tex]\(-7\)[/tex].
Split the middle term:
[tex]\[ 2a^2 - 4a - 7a + 14 \][/tex]
Group the terms:
[tex]\[ (2a^2 - 4a) - (7a - 14) \][/tex]
Factor each group:
[tex]\[ 2a(a - 2) - 7(a - 2) \][/tex]
Factor out the common term [tex]\((a - 2)\)[/tex]:
[tex]\[ (2a - 7)(a - 2) \][/tex]
So, [tex]\( 2a^2 - 11a + 14 = (2a - 7)(a - 2) \)[/tex].
### Step 2: Rewrite the Expression
Rewrite the original product using the factorization:
[tex]\[ \frac{2a - 7}{a} \times \frac{3a^2}{(2a - 7)(a - 2)} \][/tex]
### Step 3: Simplify the Expression
Now, cancel common factors:
The [tex]\((2a - 7)\)[/tex] term in the numerator and denominator cancel out:
[tex]\[ \frac{2a - 7}{a} \times \frac{3a^2}{(2a - 7)(a - 2)} = \frac{1}{a} \times \frac{3a^2}{a - 2} = \frac{3a^2}{a(a - 2)} \][/tex]
Further simplifying:
[tex]\[ \frac{3a^2}{a(a - 2)} = \frac{3a}{a - 2} \][/tex]
### Step 4: Identify the Correct Option
The simplified product of:
[tex]\[ \frac{2a - 7}{a} \times \frac{3a^2}{(2a - 7)(a - 2)} \][/tex]
is:
[tex]\[ \frac{3a}{a - 2} \][/tex]
So, the answer is:
[tex]\[ \frac{3a}{a - 2} \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Your search for answers ends at IDNLearn.com. Thanks for visiting, and we look forward to helping you again soon.