Let's break down the statements to determine the output.
Given the C code:
```c
char x[] = "hello hi";
printf("%d %d", sizeof(x), sizeof(x));
```
1. Analyzing `sizeof(x)`:
- `x` is declared as a character array `char x[] = "hello hi";`.
- When we use `(x)`, it dereferences the array `x` to the first element of the array, which is a character 'h'.
- In C, the `sizeof` operator returns the size of a data type or an expression in bytes.
- The size of a single character (`char`) is 1 byte.
- Therefore, `sizeof(x)` evaluates to `1`.
2. Analyzing `sizeof(x)`:
- Here, `x` is the array `char x[] = "hello hi";`.
- The `sizeof` operator applied to an array returns the total size of the array.
- The string `"hello hi"` consists of 8 characters plus a null terminator `\0` that signals the end of the string.
- Altogether, the array has 9 elements (8 characters + 1 null terminator).
- The size of this character array is 9 bytes.
- Therefore, `sizeof(x)` evaluates to `9`.
3. Output of `printf("%d %d", sizeof(x), sizeof(x))`:
- The first placeholder `%d` is replaced by the value of `sizeof(x)`, which is 1.
- The second placeholder `%d` is replaced by the value of `sizeof(x)`, which is 9.
- The resultant output will be: `1 9`.
So, the correct result is `1 9`.
Given the choices, none of them directly match the output `1 9`. It seems there might be an issue with the provided options. Based on the code provided and the analysis, the correct detailed breakdown shows that the answer should be `1 9`.
