Get the information you need with the help of IDNLearn.com's extensive Q&A platform. Our platform offers reliable and detailed answers, ensuring you have the information you need.
Sagot :
To find the frequency of a radiation given its wavenumber, we can use the relationship between wavenumber and frequency. The wavenumber ([tex]\(\bar{\nu}\)[/tex]) is defined as the number of wavelengths per unit distance, and is typically measured in [tex]\( \text{cm}^{-1} \)[/tex]. The formula to convert wavenumber to frequency ([tex]\(\nu\)[/tex]) is given by:
[tex]\[ \nu = \bar{\nu} \cdot c \][/tex]
where:
- [tex]\(\nu\)[/tex] is the frequency.
- [tex]\(\bar{\nu}\)[/tex] is the wavenumber.
- [tex]\(c\)[/tex] is the speed of light.
The speed of light, [tex]\(c\)[/tex], is [tex]\(2.998 \times 10^{10} \, \text{cm/s}\)[/tex].
Given:
[tex]\[ \bar{\nu} = 97540 \, \text{cm}^{-1} \][/tex]
Now, substituting the given values into the formula:
[tex]\[ \nu = 97540 \, \text{cm}^{-1} \times 2.998 \times 10^{10} \, \text{cm/s} \][/tex]
When this calculation is performed (multiplying 97540 by 2.998 and the power of 10 terms), the result is:
[tex]\[ \nu \approx 2.9242492 \times 10^{15} \, \text{s}^{-1} \][/tex]
Therefore, the correct answer is:
2) [tex]\(2.926 \times 10^{15} \, \text{s}^{-1} \)[/tex]
This matches the calculated frequency closely because the given answer choice is closest to the exact frequency calculated above.
[tex]\[ \nu = \bar{\nu} \cdot c \][/tex]
where:
- [tex]\(\nu\)[/tex] is the frequency.
- [tex]\(\bar{\nu}\)[/tex] is the wavenumber.
- [tex]\(c\)[/tex] is the speed of light.
The speed of light, [tex]\(c\)[/tex], is [tex]\(2.998 \times 10^{10} \, \text{cm/s}\)[/tex].
Given:
[tex]\[ \bar{\nu} = 97540 \, \text{cm}^{-1} \][/tex]
Now, substituting the given values into the formula:
[tex]\[ \nu = 97540 \, \text{cm}^{-1} \times 2.998 \times 10^{10} \, \text{cm/s} \][/tex]
When this calculation is performed (multiplying 97540 by 2.998 and the power of 10 terms), the result is:
[tex]\[ \nu \approx 2.9242492 \times 10^{15} \, \text{s}^{-1} \][/tex]
Therefore, the correct answer is:
2) [tex]\(2.926 \times 10^{15} \, \text{s}^{-1} \)[/tex]
This matches the calculated frequency closely because the given answer choice is closest to the exact frequency calculated above.
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.