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Sagot :
Answer:
Let's analyze the problem:
* The number is divisible by 3.
* When divided by 5, it leaves a remainder of 4.
* When divided by 11, it leaves a remainder of 7.
Understanding the problem:
To find the number, we need to find a number that satisfies all three conditions. We can approach this systematically.
Solution:
* Divisible by 3: The number must be a multiple of 3.
* Possible two-digit multiples of 3 are: 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99.
* Remainder of 4 when divided by 5:
* We can eliminate numbers from the list that don't leave a remainder of 4 when divided by 5.
* This leaves us with: 24, 39, 64, 79, 94.
* Remainder of 7 when divided by 11:
* Now, we check the remaining numbers to see which one leaves a remainder of 7 when divided by 11.
* Only 79 satisfies this condition.
Therefore, the number is 79.
To verify:
* 79 divided by 3 gives a remainder of 0.
* 79 divided by 5 gives a remainder of 4.
* 79 divided by 11 gives a remainder of 7.
So, the answer is correct.
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