To solve the given problem, we need to find the probability that a randomly selected car with no 4-wheel drive has third-row seats. We follow these steps:
1. Identify the relevant data from the table:
- The total number of cars with no 4-wheel drive: 40
- The number of cars with no 4-wheel drive that have third-row seats: 12
2. Set up the probability formula:
The probability of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.
Here, the event is selecting a car with no 4-wheel drive that has third-row seats. So the formula is:
[tex]\[
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}
\][/tex]
3. Substitute the values into the formula:
[tex]\[
\text{Probability} = \frac{12}{40}
\][/tex]
4. Simplify the fraction:
[tex]\[
\frac{12}{40} = \frac{3}{10} = 0.3
\][/tex]
So, the probability that a randomly selected car with no 4-wheel drive has third-row seats is [tex]\( 0.3 \)[/tex].
Thus, the correct answer is [tex]\( 0.3 \)[/tex].
