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The table shows the results of a student survey done by the chef at a school cafeteria. What is the probability that one of these students is female and likes peas?

\begin{tabular}{|l|c|c|c|}
\hline & Likes peas & Dislikes peas & Total \\
\hline Male & 58 & 42 & 100 \\
\hline Female & 64 & 36 & 100 \\
\hline Total & 122 & 78 & 200 \\
\hline
\end{tabular}

A. [tex]$32 \%$[/tex]

B. [tex]$36 \%$[/tex]

C. [tex]$18 \%$[/tex]

D. [tex]$64 \%$[/tex]


Sagot :

To determine the probability that a randomly selected student from the survey is a female and likes peas, we follow these steps:

1. Identify the numbers involved:
- The total number of students in the survey is [tex]\( 200 \)[/tex].
- The number of female students who like peas is [tex]\( 64 \)[/tex].

2. Set up the probability formula:
The probability [tex]\( P \)[/tex] of selecting a female student who likes peas is given by:
[tex]\[ P = \frac{\text{Number of female students who like peas}}{\text{Total number of students}} \][/tex]

3. Substitute the numbers:
[tex]\[ P = \frac{64}{200} \][/tex]

4. Convert the fraction to a percentage:
[tex]\[ P = \frac{64}{200} \times 100\% \][/tex]

5. Calculate the result:
[tex]\[ P = 32\% \][/tex]

Therefore, the probability that a randomly chosen student is female and likes peas is [tex]\( 32\% \)[/tex].

Hence, the correct answer is:
A. [tex]\( 32\% \)[/tex]
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