IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Ask any question and get a thorough, accurate answer from our community of experienced professionals.

Use the following table to evaluate the derivative.

\begin{tabular}{|c|c|c|c|c|}
\hline
[tex]$x$[/tex] & [tex]$f(x)$[/tex] & [tex]$f^{\prime}(x)$[/tex] & [tex]$g(x)$[/tex] & [tex]$g^{\prime}(x)$[/tex] \\
\hline
2 & 4 & -6 & -10 & 1 \\
\hline
\end{tabular}

Find [tex]\((f \cdot g)^{\prime}(2)\)[/tex]. If necessary, round to two decimal places.

Type your answer...


Sagot :

To find [tex]\((f \cdot g)^{\prime}(2)\)[/tex], we need to use the product rule for derivatives. The product rule states:

[tex]\[(f \cdot g)^{\prime}(x) = f^{\prime}(x) \cdot g(x) + f(x) \cdot g^{\prime}(x)\][/tex]

Given the table with the following values at [tex]\(x = 2\)[/tex]:

[tex]\[ f(2) = 4 \][/tex]
[tex]\[ f^{\prime}(2) = -6 \][/tex]
[tex]\[ g(2) = -10 \][/tex]
[tex]\[ g^{\prime}(2) = 1 \][/tex]

We can substitute these values into the product rule formula.

Step-by-step calculation:

1. Calculate [tex]\(f^{\prime}(2) \cdot g(2)\)[/tex]:
[tex]\[ f^{\prime}(2) \cdot g(2) = -6 \cdot (-10) = 60 \][/tex]

2. Calculate [tex]\(f(2) \cdot g^{\prime}(2)\)[/tex]:
[tex]\[ f(2) \cdot g^{\prime}(2) = 4 \cdot 1 = 4 \][/tex]

3. Add the results from steps 1 and 2:
[tex]\[ (f \cdot g)^{\prime}(2) = 60 + 4 = 64 \][/tex]

So, [tex]\((f \cdot g)^{\prime}(2) = 64\)[/tex].
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.