Find answers to your most challenging questions with the help of IDNLearn.com's experts. Get the information you need from our experts, who provide reliable and detailed answers to all your questions.
Sagot :
Sure, let's determine the electron configurations for Silicon (Si) and Yttrium (Y) in noble-gas notation. I will guide you through the process step-by-step.
### Silicon (Si)
1. Determine the atomic number: Silicon has an atomic number of 14.
2. Write out the full electron configuration:
- The first 2 electrons go into the 1s orbital: [tex]\(1s^2\)[/tex]
- The next 2 electrons go into the 2s orbital: [tex]\(2s^2\)[/tex]
- The next 6 electrons fill the 2p orbital: [tex]\(2p^6\)[/tex]
- The next 2 electrons occupy the 3s orbital: [tex]\(3s^2\)[/tex]
- The final 2 electrons go into the 3p orbital: [tex]\(3p^2\)[/tex]
Therefore, the full electron configuration is: [tex]\(1s^2 2s^2 2p^6 3s^2 3p^2\)[/tex]
3. Convert to noble-gas notation:
- The nearest preceding noble gas to silicon is Neon (Ne), which has the electron configuration [tex]\(1s^2 2s^2 2p^6\)[/tex].
- Thus, we can write Silicon's electron configuration in noble-gas notation as: [tex]\([Ne] 3s^2 3p^2\)[/tex]
So, the correct noble-gas notation for Silicon is:
[tex]\[ [Ne] 3s^2 3p^2 \][/tex]
### Yttrium (Y)
1. Determine the atomic number: Yttrium has an atomic number of 39.
2. Write out the full electron configuration:
- The first 2 electrons fill the 1s orbital: [tex]\(1s^2\)[/tex]
- The next 2 electrons fill the 2s orbital: [tex]\(2s^2\)[/tex]
- The next 6 electrons fill the 2p orbital: [tex]\(2p^6\)[/tex]
- The next 2 electrons fill the 3s orbital: [tex]\(3s^2\)[/tex]
- The next 6 electrons fill the 3p orbital: [tex]\(3p^6\)[/tex]
- The next 2 electrons fill the 4s orbital: [tex]\(4s^2\)[/tex]
- The next 10 electrons fill the 3d orbital: [tex]\(3d^{10}\)[/tex]
- The next 6 electrons fill the 4p orbital: [tex]\(4p^6\)[/tex]
- The next 2 electrons fill the 5s orbital: [tex]\(5s^2\)[/tex]
- The final electron goes into the 4d orbital: [tex]\(4d^1\)[/tex]
Therefore, the full electron configuration is:
[tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^1\)[/tex]
3. Convert to noble-gas notation:
- The nearest preceding noble gas to yttrium is Krypton (Kr), which has the electron configuration [tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6\)[/tex].
- Thus, we can write Yttrium's electron configuration in noble-gas notation as: [tex]\([Kr] 5s^2 4d^1\)[/tex]
So, the correct noble-gas notation for Yttrium is:
[tex]\[ [Kr] 5s^2 4d^1 \][/tex]
If you have any questions or need further clarification, feel free to ask!
### Silicon (Si)
1. Determine the atomic number: Silicon has an atomic number of 14.
2. Write out the full electron configuration:
- The first 2 electrons go into the 1s orbital: [tex]\(1s^2\)[/tex]
- The next 2 electrons go into the 2s orbital: [tex]\(2s^2\)[/tex]
- The next 6 electrons fill the 2p orbital: [tex]\(2p^6\)[/tex]
- The next 2 electrons occupy the 3s orbital: [tex]\(3s^2\)[/tex]
- The final 2 electrons go into the 3p orbital: [tex]\(3p^2\)[/tex]
Therefore, the full electron configuration is: [tex]\(1s^2 2s^2 2p^6 3s^2 3p^2\)[/tex]
3. Convert to noble-gas notation:
- The nearest preceding noble gas to silicon is Neon (Ne), which has the electron configuration [tex]\(1s^2 2s^2 2p^6\)[/tex].
- Thus, we can write Silicon's electron configuration in noble-gas notation as: [tex]\([Ne] 3s^2 3p^2\)[/tex]
So, the correct noble-gas notation for Silicon is:
[tex]\[ [Ne] 3s^2 3p^2 \][/tex]
### Yttrium (Y)
1. Determine the atomic number: Yttrium has an atomic number of 39.
2. Write out the full electron configuration:
- The first 2 electrons fill the 1s orbital: [tex]\(1s^2\)[/tex]
- The next 2 electrons fill the 2s orbital: [tex]\(2s^2\)[/tex]
- The next 6 electrons fill the 2p orbital: [tex]\(2p^6\)[/tex]
- The next 2 electrons fill the 3s orbital: [tex]\(3s^2\)[/tex]
- The next 6 electrons fill the 3p orbital: [tex]\(3p^6\)[/tex]
- The next 2 electrons fill the 4s orbital: [tex]\(4s^2\)[/tex]
- The next 10 electrons fill the 3d orbital: [tex]\(3d^{10}\)[/tex]
- The next 6 electrons fill the 4p orbital: [tex]\(4p^6\)[/tex]
- The next 2 electrons fill the 5s orbital: [tex]\(5s^2\)[/tex]
- The final electron goes into the 4d orbital: [tex]\(4d^1\)[/tex]
Therefore, the full electron configuration is:
[tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^1\)[/tex]
3. Convert to noble-gas notation:
- The nearest preceding noble gas to yttrium is Krypton (Kr), which has the electron configuration [tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6\)[/tex].
- Thus, we can write Yttrium's electron configuration in noble-gas notation as: [tex]\([Kr] 5s^2 4d^1\)[/tex]
So, the correct noble-gas notation for Yttrium is:
[tex]\[ [Kr] 5s^2 4d^1 \][/tex]
If you have any questions or need further clarification, feel free to ask!
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.
