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Verify the following equation:

[tex]\[ \frac{1}{1.3} + \frac{1}{2.5} + \frac{1}{3.7} + \frac{1}{4.9} + \ldots = 2(1 - \ln 2) \][/tex]


Sagot :

To determine if the given series [tex]\(\frac{1}{1.3}+\frac{1}{2.5}+\frac{1}{3.7}+\frac{1}{4.9}+\ldots\)[/tex] equals [tex]\(2(1 - \ln 2)\)[/tex], let's examine the terms of the series and whether their sum matches the expression on the right-hand side.

### Step-by-Step Solution

1. Collection of Terms:
The series begins with the following terms:
[tex]\[ \frac{1}{1.3}, \frac{1}{2.5}, \frac{1}{3.7}, \frac{1}{4.9} \][/tex]

2. Calculating Each Term:

- First term:
[tex]\[ \frac{1}{1.3} \approx 0.7692307692307692 \][/tex]

- Second term:
[tex]\[ \frac{1}{2.5} = 0.4 \][/tex]

- Third term:
[tex]\[ \frac{1}{3.7} \approx 0.27027027027027023 \][/tex]

- Fourth term:
[tex]\[ \frac{1}{4.9} \approx 0.2040816326530612 \][/tex]

3. Summing the Terms:
To find the sum of the series up to the given terms:
[tex]\[ 0.7692307692307692 + 0.4 + 0.27027027027027023 + 0.2040816326530612 \approx 1.6435826721541007 \][/tex]

4. Comparing with the Given Expression:

The given expression is [tex]\(2(1 - \ln 2)\)[/tex]. To see if our calculated sum is equal to it, let's first compute the numerical value of the right-hand side.

- Calculating [tex]\(1 - \ln 2\)[/tex]:
[tex]\[ \ln 2 \approx 0.6931471805599453 \][/tex]
[tex]\[ 1 - 0.6931471805599453 \approx 0.3068528194400547 \][/tex]

- Then multiply by 2:
[tex]\[ 2 \times 0.3068528194400547 \approx 0.6137056388801094 \][/tex]

Since the sum of the series up to the given terms is approximately [tex]\(1.6435826721541007\)[/tex] and the evaluated right-hand side is about [tex]\(0.6137056388801094\)[/tex], they are not equal.

### Conclusion
The sum of the given terms of the series [tex]\(\frac{1}{1.3}+\frac{1}{2.5}+\frac{1}{3.7}+\frac{1}{4.9}+\ldots\)[/tex] does not equal [tex]\(2(1 - \ln 2)\)[/tex]. The value of the sum of the series terms is approximately [tex]\(1.6435826721541007\)[/tex], while the expression evaluates to approximately [tex]\(0.6137056388801094\)[/tex]. Hence, the statement is false.