To solve this problem, we need to calculate the density of the unknown liquid and then compare it to the known densities of the substances listed.
Step-by-Step Solution:
1. Convert the mass from kilograms to grams:
- Given mass: [tex]\( 1.65 \text{ kg} \)[/tex]
- Since [tex]\( 1 \text{ kg} = 1000 \text{ grams} \)[/tex]
- Therefore, mass in grams: [tex]\( 1.65 \times 1000 = 1650 \text{ grams} \)[/tex]
2. Calculate the density:
- Density is defined as mass divided by volume.
- Given volume: [tex]\( 1115 \text{ cm}^3 \)[/tex]
- Density of the liquid:
[tex]\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}} = \frac{1650 \text{ grams}}{1115 \text{ cm}^3}
\][/tex]
- Perform the division:
[tex]\[
\text{Density} \approx 1.480 \frac{\text{grams}}{\text{cm}^3}
\][/tex]
- Round the result to 3 significant digits:
[tex]\[
1.48 \frac{\text{grams}}{\text{cm}^3}
\][/tex]
3. Compare the calculated density with the given densities:
- Methyl acetate: [tex]\( 0.93 \frac{\text{g}}{\text{mL}} \)[/tex]
- Carbon tetrachloride: [tex]\( 1.6 \frac{\text{g}}{\text{mL}} \)[/tex]
- Diethylamine: [tex]\( 0.71 \frac{\text{g}}{\text{mL}} \)[/tex]
- Glycerol: [tex]\( 1.3 \frac{\text{g}}{\text{mL}} \)[/tex]
- Chloroform: [tex]\( 1.5 \frac{\text{g}}{\text{mL}} \)[/tex]
4. Identify the closest match:
- The calculated density is [tex]\( 1.48 \frac{\text{g}}{\text{mL}} \)[/tex].
- Compared to the given densities, it is closest to chloroform which has a density of [tex]\( 1.5 \frac{\text{g}}{\text{mL}} \)[/tex].
Conclusion:
- The density of the unknown liquid is [tex]\( 1.48 \frac{\text{g}}{\text{mL}} \)[/tex].
- Based on the densities provided in the MSDS, the unknown liquid is most likely chloroform.
