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What is the pOH of a solution with [tex]\left[ OH ^{-}\right] = 1.4 \times 10^{-13}[/tex]?

A. 12.85
B. 13.15
C. 14.00
D. -13.15


Sagot :

To determine the pOH of a solution with a hydroxide ion concentration [tex]\(\left[ OH^- \right]= 1.4 \times 10^{-13}\)[/tex] M, we follow these steps:

1. Understanding the Relationship: The pOH is calculated from the concentration of hydroxide ions using the formula:
[tex]\[ \text{pOH} = -\log \left[ OH^- \right] \][/tex]

2. Substitute the Given Value: Substitute the given hydroxide ion concentration into the formula:
[tex]\[ \text{pOH} = -\log \left( 1.4 \times 10^{-13} \right) \][/tex]

3. Calculate the Logarithm: To find the pOH, calculate the logarithm (base 10) of the hydroxide concentration. The logarithmic calculation yields a pOH value.

4. Result and Options Comparison: After computation, the resulting pOH value is approximately 12.85.

Therefore, the pOH of the solution is:

A. 12.85