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Graph the parabola:
[tex]\[ y = -2(x + 5)^2 + 1 \][/tex]

Plot five points on the parabola: the vertex, two points to the left of the vertex, and two points to the right of the vertex. Then, click on the graph-a-function button.


Sagot :

To graph the parabola defined by the equation:

[tex]\[ y = -2(x + 5)^2 + 1 \][/tex]

we start by finding the vertex and choosing specific points to plot on either side of the vertex. Here is a step-by-step solution for finding these points:

1. Identify the Vertex:
The vertex form of a parabola is given by [tex]\( y = a(x - h)^2 + k \)[/tex]. Comparing this with our equation [tex]\( y = -2(x + 5)^2 + 1 \)[/tex]:

- [tex]\( h = -5 \)[/tex]
- [tex]\( k = 1 \)[/tex]

Therefore, the vertex of the parabola is at [tex]\( (-5, 1) \)[/tex].

2. Calculate Points to the Left of the Vertex:

- For [tex]\( x = -6 \)[/tex]:
[tex]\[ y = -2(-6 + 5)^2 + 1 = -2(-1)^2 + 1 = -2(1) + 1 = -1 \][/tex]
Hence, the point is [tex]\( (-6, -1) \)[/tex].

- For [tex]\( x = -7 \)[/tex]:
[tex]\[ y = -2(-7 + 5)^2 + 1 = -2(-2)^2 + 1 = -2(4) + 1 = -7 \][/tex]
Hence, the point is [tex]\( (-7, -7) \)[/tex].

3. Calculate Points to the Right of the Vertex:

- For [tex]\( x = -4 \)[/tex]:
[tex]\[ y = -2(-4 + 5)^2 + 1 = -2(1)^2 + 1 = -2(1) + 1 = -1 \][/tex]
Hence, the point is [tex]\( (-4, -1) \)[/tex].

- For [tex]\( x = -3 \)[/tex]:
[tex]\[ y = -2(-3 + 5)^2 + 1 = -2(2)^2 + 1 = -2(4) + 1 = -7 \][/tex]
Hence, the point is [tex]\( (-3, -7) \)[/tex].

4. Summary of Points on the Parabola:

- Vertex: [tex]\( (-5, 1) \)[/tex]
- Points to the left: [tex]\( (-6, -1) \)[/tex], [tex]\( (-7, -7) \)[/tex]
- Points to the right: [tex]\( (-4, -1) \)[/tex], [tex]\( (-3, -7) \)[/tex]

These points provide a clear representation of the parabola's shape. When you plot these points on a graph, you’d connect them to visualize a downward-opening parabola centered on [tex]\( (-5, 1) \)[/tex]. The five points you need to plot are:

[tex]\[ (-5, 1), (-6, -1), (-7, -7), (-4, -1), (-3, -7) \][/tex]

Once you plot these points, you will observe the parabolic shape forming. The vertex is the highest point, and the parabola opens downwards because the coefficient of the squared term ([tex]\( -2 \)[/tex]) is negative.