IDNLearn.com is your go-to platform for finding reliable answers quickly. Ask your questions and receive accurate, in-depth answers from our knowledgeable community members.
Sagot :
To convert the density from pounds per cubic foot (lb/ft³) to kilograms per cubic meter (kg/m³), you need to use two conversion ratios: one for mass and one for volume. The relevant ratios are:
- [tex]\(\frac{1 \text{ kg}}{2.2 \text{ lb}}\)[/tex]
- [tex]\(\frac{1 \text{ m}^3}{35.3 \text{ ft}^3}\)[/tex]
Given that the density is 167 lb/ft³, let's place these in the equation to get the density in kg/m³:
[tex]\[ 167 \frac{\text{lb}}{\text{ft}^3} \times \frac{1 \text{ kg}}{2.2 \text{ lb}} \times \frac{1 \text{m}^3}{35.3 \text{ft}^3} = ? \frac{\text{kg}}{\text{m}^3} \][/tex]
To solve this:
1. Multiply 167 by [tex]\(\frac{1 \text{ kg}}{2.2 \text{ lb}}\)[/tex]:
[tex]\[ 167 \times \frac{1 \text{ kg}}{2.2 \text{ lb}} = 75.9090909090909 \frac{\text{kg}}{\text{ft}^3} \][/tex]
2. Now, take the result and multiply by [tex]\(\frac{1 \text{ m}^3}{35.3 \text{ ft}^3}\)[/tex]:
[tex]\[ 75.9090909090909 \times \frac{1 \text{ m}^3}{35.3 \text{ ft}^3} = 2.15039917589493 \frac{\text{kg}}{\text{m}^3} \][/tex]
Thus, the crate's density in kilograms per cubic meter is:
[tex]\[ 2.15039917589493 \frac{\text{kg}}{\text{m}^3} \][/tex]
Rounded to the nearest hundredth, the density is:
[tex]\[ 2.15 \frac{\text{kg}}{\text{m}^3} \][/tex]
Therefore, the final answer, rounded to the nearest hundredth, is:
[tex]\[ 2.15 \frac{\text{kg}}{\text{m}^3} \][/tex]
- [tex]\(\frac{1 \text{ kg}}{2.2 \text{ lb}}\)[/tex]
- [tex]\(\frac{1 \text{ m}^3}{35.3 \text{ ft}^3}\)[/tex]
Given that the density is 167 lb/ft³, let's place these in the equation to get the density in kg/m³:
[tex]\[ 167 \frac{\text{lb}}{\text{ft}^3} \times \frac{1 \text{ kg}}{2.2 \text{ lb}} \times \frac{1 \text{m}^3}{35.3 \text{ft}^3} = ? \frac{\text{kg}}{\text{m}^3} \][/tex]
To solve this:
1. Multiply 167 by [tex]\(\frac{1 \text{ kg}}{2.2 \text{ lb}}\)[/tex]:
[tex]\[ 167 \times \frac{1 \text{ kg}}{2.2 \text{ lb}} = 75.9090909090909 \frac{\text{kg}}{\text{ft}^3} \][/tex]
2. Now, take the result and multiply by [tex]\(\frac{1 \text{ m}^3}{35.3 \text{ ft}^3}\)[/tex]:
[tex]\[ 75.9090909090909 \times \frac{1 \text{ m}^3}{35.3 \text{ ft}^3} = 2.15039917589493 \frac{\text{kg}}{\text{m}^3} \][/tex]
Thus, the crate's density in kilograms per cubic meter is:
[tex]\[ 2.15039917589493 \frac{\text{kg}}{\text{m}^3} \][/tex]
Rounded to the nearest hundredth, the density is:
[tex]\[ 2.15 \frac{\text{kg}}{\text{m}^3} \][/tex]
Therefore, the final answer, rounded to the nearest hundredth, is:
[tex]\[ 2.15 \frac{\text{kg}}{\text{m}^3} \][/tex]
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.