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Which point lies on the circle represented by the equation [tex]$x^2+(y-12)^2=25^2$[/tex]?

A. [tex][tex]$(20,-3)$[/tex][/tex]
B. [tex]$(-7,24)$[/tex]
C. [tex]$(0,13)$[/tex]
D. [tex][tex]$(-25,-13)$[/tex][/tex]


Sagot :

To determine which point lies on the circle represented by the equation [tex]\( x^2 + (y - 12)^2 = 25^2 \)[/tex], we need to check if each point satisfies the circle's equation.

Given points:
- [tex]\( (20, -3) \)[/tex]
- [tex]\( (-7, 24) \)[/tex]
- [tex]\( (0, 13) \)[/tex]
- [tex]\( (-25, -13) \)[/tex]

Substituting these points into the equation [tex]\( x^2 + (y - 12)^2 = 625 \)[/tex], we get:

1. For the point [tex]\( (20, -3) \)[/tex]:
[tex]\[ x = 20, \quad y = -3 \][/tex]
[tex]\[ 20^2 + (-3 - 12)^2 = 400 + (-15)^2 = 400 + 225 = 625 \][/tex]
[tex]\[ 625 = 625 \][/tex]
[tex]\( (20, -3) \)[/tex] satisfies the equation of the circle.

2. For the point [tex]\( (-7, 24) \)[/tex]:
[tex]\[ x = -7, \quad y = 24 \][/tex]
[tex]\[ (-7)^2 + (24 - 12)^2 = 49 + 12^2 = 49 + 144 = 193 \][/tex]
[tex]\[ 193 \neq 625 \][/tex]
[tex]\( (-7, 24) \)[/tex] does not satisfy the equation of the circle.

3. For the point [tex]\( (0, 13) \)[/tex]:
[tex]\[ x = 0, \quad y = 13 \][/tex]
[tex]\[ 0^2 + (13 - 12)^2 = 0 + 1 = 1 \][/tex]
[tex]\[ 1 \neq 625 \][/tex]
[tex]\( (0, 13) \)[/tex] does not satisfy the equation of the circle.

4. For the point [tex]\( (-25, -13) \)[/tex]:
[tex]\[ x = -25, \quad y = -13 \][/tex]
[tex]\[ (-25)^2 + (-13 - 12)^2 = 625 + (-25)^2 = 625 + 625 = 1250 \][/tex]
[tex]\[ 1250 \neq 625 \][/tex]
[tex]\( (-25, -13) \)[/tex] does not satisfy the equation of the circle.

Conclusively, the only point that lies on the circle [tex]\( x^2 + (y - 12)^2 = 625 \)[/tex] is [tex]\( (20, -3) \)[/tex].

Thus, the correct answer is:
A. [tex]\( (20, -3) \)[/tex]