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Sagot :
Certainly! Let's make [tex]\(b\)[/tex] the subject of the given equation:
[tex]\[ A = \frac{1}{2} h (a \cdot b) \][/tex]
Here are the steps:
1. Starting with the given equation:
[tex]\[ A = \frac{1}{2} h (a \cdot b) \][/tex]
2. Eliminate the fraction by multiplying both sides by 2:
[tex]\[ 2A = h (a \cdot b) \][/tex]
3. Isolate [tex]\(b\)[/tex] by dividing both sides by [tex]\(h \cdot a\)[/tex]:
[tex]\[ b = \frac{2A}{h \cdot a} \][/tex]
So, the value of [tex]\(b\)[/tex] in terms of [tex]\(A\)[/tex], [tex]\(h\)[/tex], and [tex]\(a\)[/tex] is:
[tex]\[ b = \frac{2A}{a \cdot h} \][/tex]
This expresses [tex]\(b\)[/tex] as the subject of the given equation.
[tex]\[ A = \frac{1}{2} h (a \cdot b) \][/tex]
Here are the steps:
1. Starting with the given equation:
[tex]\[ A = \frac{1}{2} h (a \cdot b) \][/tex]
2. Eliminate the fraction by multiplying both sides by 2:
[tex]\[ 2A = h (a \cdot b) \][/tex]
3. Isolate [tex]\(b\)[/tex] by dividing both sides by [tex]\(h \cdot a\)[/tex]:
[tex]\[ b = \frac{2A}{h \cdot a} \][/tex]
So, the value of [tex]\(b\)[/tex] in terms of [tex]\(A\)[/tex], [tex]\(h\)[/tex], and [tex]\(a\)[/tex] is:
[tex]\[ b = \frac{2A}{a \cdot h} \][/tex]
This expresses [tex]\(b\)[/tex] as the subject of the given equation.
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