Explore a wide range of topics and get answers from experts on IDNLearn.com. Discover in-depth and trustworthy answers from our extensive network of knowledgeable professionals.
Sagot :
To solve the equation [tex]\( e^x - x e^{5x - 1} = 0 \)[/tex], follow these steps:
1. Rewrite the equation:
Given equation:
[tex]\[ e^x - x e^{5x - 1} = 0 \][/tex]
2. Isolate one term involving [tex]\( e^x \)[/tex]:
Move [tex]\( x e^{5x - 1} \)[/tex] to the right side of the equation:
[tex]\[ e^x = x e^{5x - 1} \][/tex]
3. Express the equation in a form involving Lambert W function:
Recall that the Lambert W function is defined as the inverse function of [tex]\( z = W(z) e^{W(z)} \)[/tex]. We aim to use this form to our advantage.
First, we simplify the right-hand side:
[tex]\[ e^x = x e^{5x - 1} \][/tex]
Rewrite the exponent on the right-hand side:
[tex]\[ e^x = x e^{5x} e^{-1} \][/tex]
Multiply both sides by [tex]\( e \)[/tex] to simplify:
[tex]\[ e \cdot e^x = x e^{5x} \][/tex]
Simplify the left-hand side:
[tex]\[ e^{x + 1} = x e^{5x} \][/tex]
4. Isolate the exponential term:
Divide both sides by [tex]\( e^{5x} \)[/tex]:
[tex]\[ \frac{e^{x+1}}{e^{5x}} = x \][/tex]
Simplify the left-hand side:
[tex]\[ e^{x + 1 - 5x} = x \][/tex]
Simplify the exponent:
[tex]\[ e^{1 - 4x} = x \][/tex]
5. Introduce the Lambert W function:
To solve for [tex]\( x \)[/tex] using the Lambert W function, set [tex]\( 1 - 4x = -t \)[/tex], so:
[tex]\[ e^{-t} = x \][/tex]
This gives us:
[tex]\[ x e^t = 1 \][/tex]
Replace [tex]\( x \)[/tex] with [tex]\( e^{-t} \)[/tex]:
[tex]\[ e^{-t} e^t = 1 \][/tex]
Simplify:
[tex]\[ e^0 = 1 \][/tex]
Hence:
[tex]\[ x = e^{-t} \][/tex]
6. Express [tex]\( t \)[/tex] in terms of [tex]\( x \)[/tex]:
Recall [tex]\( t = 1 - 4x \)[/tex], so:
[tex]\[ t = 1 - 4x \][/tex]
[tex]\( -t = - (1 - 4x) \)[/tex], thus:
[tex]\[ x = e^{-(1 - 4x)} \][/tex]
Therefore, rewrite it as:
[tex]\[ x = e^{4x - 1} \][/tex]
7. Apply the Lambert W function:
Recall the natural logarithm form:
[tex]\[ 4x - 1 = W(1) = W(e^{4x - 1}) \][/tex]
Solving it for [tex]\( x \)[/tex] results in:
[tex]\[ x = \frac{W(e^4)}{4} = \frac{W(4e)}{4} \][/tex]
Therefore, the solution to the equation [tex]\( e^x - x e^{5x - 1} = 0 \)[/tex] is:
[tex]\[ x = \frac{\text{LambertW}(4e)}{4} \][/tex]
1. Rewrite the equation:
Given equation:
[tex]\[ e^x - x e^{5x - 1} = 0 \][/tex]
2. Isolate one term involving [tex]\( e^x \)[/tex]:
Move [tex]\( x e^{5x - 1} \)[/tex] to the right side of the equation:
[tex]\[ e^x = x e^{5x - 1} \][/tex]
3. Express the equation in a form involving Lambert W function:
Recall that the Lambert W function is defined as the inverse function of [tex]\( z = W(z) e^{W(z)} \)[/tex]. We aim to use this form to our advantage.
First, we simplify the right-hand side:
[tex]\[ e^x = x e^{5x - 1} \][/tex]
Rewrite the exponent on the right-hand side:
[tex]\[ e^x = x e^{5x} e^{-1} \][/tex]
Multiply both sides by [tex]\( e \)[/tex] to simplify:
[tex]\[ e \cdot e^x = x e^{5x} \][/tex]
Simplify the left-hand side:
[tex]\[ e^{x + 1} = x e^{5x} \][/tex]
4. Isolate the exponential term:
Divide both sides by [tex]\( e^{5x} \)[/tex]:
[tex]\[ \frac{e^{x+1}}{e^{5x}} = x \][/tex]
Simplify the left-hand side:
[tex]\[ e^{x + 1 - 5x} = x \][/tex]
Simplify the exponent:
[tex]\[ e^{1 - 4x} = x \][/tex]
5. Introduce the Lambert W function:
To solve for [tex]\( x \)[/tex] using the Lambert W function, set [tex]\( 1 - 4x = -t \)[/tex], so:
[tex]\[ e^{-t} = x \][/tex]
This gives us:
[tex]\[ x e^t = 1 \][/tex]
Replace [tex]\( x \)[/tex] with [tex]\( e^{-t} \)[/tex]:
[tex]\[ e^{-t} e^t = 1 \][/tex]
Simplify:
[tex]\[ e^0 = 1 \][/tex]
Hence:
[tex]\[ x = e^{-t} \][/tex]
6. Express [tex]\( t \)[/tex] in terms of [tex]\( x \)[/tex]:
Recall [tex]\( t = 1 - 4x \)[/tex], so:
[tex]\[ t = 1 - 4x \][/tex]
[tex]\( -t = - (1 - 4x) \)[/tex], thus:
[tex]\[ x = e^{-(1 - 4x)} \][/tex]
Therefore, rewrite it as:
[tex]\[ x = e^{4x - 1} \][/tex]
7. Apply the Lambert W function:
Recall the natural logarithm form:
[tex]\[ 4x - 1 = W(1) = W(e^{4x - 1}) \][/tex]
Solving it for [tex]\( x \)[/tex] results in:
[tex]\[ x = \frac{W(e^4)}{4} = \frac{W(4e)}{4} \][/tex]
Therefore, the solution to the equation [tex]\( e^x - x e^{5x - 1} = 0 \)[/tex] is:
[tex]\[ x = \frac{\text{LambertW}(4e)}{4} \][/tex]
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.