To find the pH of a solution with a given hydroxide ion concentration [tex]\([OH^-] = 0.0044 \, M\)[/tex], you can follow these steps:
1. Calculate the pOH:
- The pOH is determined by taking the negative logarithm (base 10) of the hydroxide ion concentration.
[tex]\[
\text{pOH} = -\log_{10}([OH^-])
\][/tex]
- Plugging in the given concentration:
[tex]\[
\text{pOH} = -\log_{10}(0.0044)
\][/tex]
- From calculation, you find:
[tex]\[
\text{pOH} \approx 2.36
\][/tex]
2. Calculate the pH:
- The relationship between pH and pOH in any aqueous solution at 25°C (298 K) is given by:
[tex]\[
\text{pH} + \text{pOH} = 14
\][/tex]
- Using the value of pOH calculated:
[tex]\[
\text{pH} = 14 - \text{pOH}
\][/tex]
[tex]\[
\text{pH} = 14 - 2.36
\][/tex]
- So, the pH is:
[tex]\[
\text{pH} \approx 11.64
\][/tex]
Therefore, the pH of the solution with [tex]\([OH^-] = 0.0044 \, M\)[/tex] is approximately 11.64. Hence, the answer is:
11.64
