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Which of the following expressions is equivalent to [tex]\frac{-48x-8}{8x-64}[/tex]?

Choose 1 answer:

A. [tex]\frac{6x+1}{x-8}[/tex]

B. [tex]\frac{-6x+1}{x-8}[/tex]

C. [tex]\frac{-6x-1}{x-8}[/tex]

D. [tex]\frac{-6x+1}{x+8}[/tex]


Sagot :

To determine which of the given expressions is equivalent to [tex]\(\frac{-48 x - 8}{8 x - 64}\)[/tex], we can follow these steps:

### Step 1: Factor both the numerator and the denominator
1. Numerator: [tex]\(-48x - 8\)[/tex]
- Factor out the greatest common factor (GCF). Here, the GCF is [tex]\(-8\)[/tex]:
[tex]\[ -48x - 8 = -8 (6x + 1) \][/tex]

2. Denominator: [tex]\(8x - 64\)[/tex]
- Factor out the GCF, which is [tex]\(8\)[/tex]:
[tex]\[ 8 x - 64 = 8 (x - 8) \][/tex]

### Step 2: Rewrite the fraction with the factored numerator and denominator
[tex]\[ \frac{-48 x - 8}{8 x - 64} = \frac{-8 (6 x + 1)}{8 (x - 8)} \][/tex]

### Step 3: Simplify the fraction
- Notice that the [tex]\(8\)[/tex] in the denominator and the [tex]\(-8\)[/tex] in the numerator can be canceled out:
[tex]\[ \frac{-8 (6 x + 1)}{8 (x - 8)} = \frac{-(6 x + 1)}{x - 8} \][/tex]
- Simplifying this gives:
[tex]\[ \frac{-6 x - 1}{x - 8} \][/tex]

### Conclusion
The equivalent expression to [tex]\(\frac{-48 x - 8}{8 x - 64}\)[/tex] is [tex]\(\frac{-6 x - 1}{x - 8}\)[/tex].

Thus, the correct answer is:

(C) [tex]\(\frac{-6 x - 1}{x - 8}\)[/tex]